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Which element has the ground state electron configuration [Kr] 5s^2 4d^{10} 5p^2?
A
Te (Tellurium)
B
Sb (Antimony)
C
In (Indium)
D
Sn (Tin)
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1
Identify the noble gas core in the given electron configuration. Here, [Kr] represents the electron configuration of Krypton, which accounts for the first 36 electrons.
Count the electrons beyond the [Kr] core: 5s^2 means 2 electrons in the 5s subshell, 4d^{10} means 10 electrons in the 4d subshell, and 5p^2 means 2 electrons in the 5p subshell. Adding these gives 2 + 10 + 2 = 14 electrons beyond Krypton.
Add the 14 electrons beyond Krypton to the 36 electrons in Krypton to find the total number of electrons: 36 + 14 = 50 electrons.
Use the atomic number to identify the element. The element with atomic number 50 is Tin (Sn).
Confirm that the electron configuration matches the expected configuration for Tin in its ground state, which is [Kr] 5s^2 4d^{10} 5p^2.