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In the reaction between NaOH and H2SO4, how many moles of NaOH are required to completely react with 38 moles of H2SO4?
A
38 moles
B
57 moles
C
19 moles
D
76 moles
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1
Write the balanced chemical equation for the reaction between sodium hydroxide (NaOH) and sulfuric acid (H2SO4): \(\mathrm{H_2SO_4 + 2\ NaOH \rightarrow Na_2SO_4 + 2\ H_2O}\).
Identify the mole ratio between H2SO4 and NaOH from the balanced equation. For every 1 mole of H2SO4, 2 moles of NaOH are required.
Use the given amount of H2SO4 (38 moles) and multiply by the mole ratio to find the moles of NaOH needed: \(38\ \text{moles H}_2\text{SO}_4 \times \frac{2\ \text{moles NaOH}}{1\ \text{mole H}_2\text{SO}_4}\).
Set up the calculation without solving it to find the moles of NaOH required to completely react with 38 moles of H2SO4.
Interpret the result as the total moles of NaOH needed for complete neutralization of the given amount of sulfuric acid.