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How many valence electrons are present in a neutral atom of aluminum (Al)?
A
2
B
3
C
1
D
5
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1
Identify the atomic number of aluminum (Al), which is 13. This means a neutral aluminum atom has 13 electrons.
Determine the electron configuration of aluminum by filling the orbitals in order: 1s, 2s, 2p, 3s, and 3p.
Write the electron configuration for aluminum: \$1s^2 2s^2 2p^6 3s^2 3p^1$.
Recognize that valence electrons are the electrons in the outermost shell (highest principal quantum number). For aluminum, this is the third shell (3s and 3p orbitals).
Count the electrons in the 3s and 3p orbitals: \$3s^2$ and \$3p^1$, which totals 3 valence electrons.