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What are the products formed when HNO3(aq) reacts with Na2SO3(aq)?
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3. Chemical Reactions
Balancing Chemical Equations
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What is the number of each type of atom on the right side of the balanced equation 2C6H14(l) + 19O2(g) → 12CO2(g) + 14H2O(g)?
A
24 carbon, 28 hydrogen, 38 oxygen
B
6 carbon, 14 hydrogen, 19 oxygen
C
12 carbon, 28 hydrogen, 26 oxygen
D
12 carbon, 14 hydrogen, 38 oxygen
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Identify the chemical equation given: 2C6H14(l) + 19O2(g) → 12CO2(g) + 14H2O(g).
Understand that the equation is already balanced, meaning the number of atoms of each element is the same on both sides of the equation.
Count the number of carbon atoms on the right side: In 12CO2, there are 12 carbon atoms.
Count the number of hydrogen atoms on the right side: In 14H2O, there are 2 hydrogen atoms per molecule, so 14 * 2 = 28 hydrogen atoms.
Count the number of oxygen atoms on the right side: In 12CO2, there are 2 oxygen atoms per molecule, so 12 * 2 = 24 oxygen atoms. In 14H2O, there is 1 oxygen atom per molecule, so 14 * 1 = 14 oxygen atoms. Add them together: 24 + 14 = 38 oxygen atoms.
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