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Using the quadratic formula, what is the solution set of ?
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5. BONUS: Mathematical Operations and Functions
The Quadratic Formula
Scelta multipla
Using the quadratic formula, what is the solution set of ?
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Guida verificata passo dopo passo1
Identify the coefficients in the quadratic equation \(x^2 + 5x - 5 = 0\). Here, \(a = 1\), \(b = 5\), and \(c = -5\).
Recall the quadratic formula for solving $ax^2 + bx + c = 0$:
\[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]
Calculate the discriminant \(\Delta = b^2 - 4ac\). Substitute the values:
\[\Delta = (5)^2 - 4(1)(-5)\]
Simplify the discriminant expression to find its value (do not calculate the final number here, just set up the expression).
Substitute \(a\), \(b\), and the discriminant \(\Delta\) back into the quadratic formula to write the solution set as:
\[x = \frac{-5 \pm \sqrt{\Delta}}{2}\]
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