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At 25°C, the heat of fusion of aluminum is 10.6 kJ/mol and the heat of sublimation is 326.4 kJ/mol. What is the heat of vaporization of aluminum at 25°C?
A
326.4 kJ/mol
B
315.8 kJ/mol
C
337.0 kJ/mol
D
10.6 kJ/mol
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1
Understand the relationship between heat of fusion, heat of sublimation, and heat of vaporization. The heat of sublimation is the sum of the heat of fusion and the heat of vaporization.
Identify the given values: heat of fusion (ΔH_fusion) = 10.6 kJ/mol and heat of sublimation (ΔH_sublimation) = 326.4 kJ/mol.
Use the formula: ΔH_sublimation = ΔH_fusion + ΔH_vaporization to find the heat of vaporization (ΔH_vaporization).
Rearrange the formula to solve for ΔH_vaporization: ΔH_vaporization = ΔH_sublimation - ΔH_fusion.
Substitute the given values into the rearranged formula: ΔH_vaporization = 326.4 kJ/mol - 10.6 kJ/mol.