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What is the ground-state electron configuration for the vanadium 2+ ion?
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24. Transition Metals and Coordination Compounds
Electron Configurations of Transition Metals
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Write an electron configuration for ion of Tungsten (IV).
A
[Xe]6s24f145d4
B
[Xe]6s24f14
C
[Xe]6s24f145d8
D
[Xe]4f145d2
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Identify the neutral atom's electron configuration: Tungsten (W) has an atomic number of 74, so its electron configuration is [Xe]6s^24f^145d^4.
Determine the charge of the ion: Tungsten (IV) indicates a +4 charge, meaning it has lost 4 electrons.
Remove electrons starting from the outermost shell: Electrons are removed first from the 6s orbital, then from the 5d orbital.
Remove 2 electrons from the 6s orbital: This changes the configuration to [Xe]4f^145d^4.
Remove 2 more electrons from the 5d orbital: This results in the final electron configuration of [Xe]4f^145d^2 for the W^4+ ion.
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