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The equilibrium constant for the reaction 2NO(g) + Br2 ⇌ 2NOBr(g) is Kc = 2.0 × 10⁻² at a certain temperature. Calculate Kc for the reverse reaction NOBr(g) ⇌ NO(g) + 1/2Br2(g).
A
Kc = 1.0 × 10⁻²
B
Kc = 4.0 × 10⁻²
C
Kc = 5.0 × 10¹
D
Kc = 2.0 × 10⁻²
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1
Identify the given equilibrium reaction: 2NO(g) + Br2 ⇌ 2NOBr(g) with Kc = 2.0 × 10⁻².
Recognize that the problem asks for the equilibrium constant of the reverse reaction: NOBr(g) ⇌ NO(g) + 1/2Br2(g).
Understand that the equilibrium constant for a reverse reaction is the reciprocal of the equilibrium constant for the forward reaction.
Calculate the equilibrium constant for the reverse reaction by taking the reciprocal of the given Kc for the forward reaction: Kc(reverse) = 1 / Kc(forward).
Substitute the given Kc value into the reciprocal formula: Kc(reverse) = 1 / (2.0 × 10⁻²) and simplify to find the Kc for the reverse reaction.