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What volume of a 2.00 M solution of sulfuric acid is needed to provide 0.0500 mol of sulfuric acid?
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6. Chemical Quantities & Aqueous Reactions
Molarity
Scelta multipla
Wine contains 13.5% v/v of ethanol (C2H5OH). What is the molarity of ethanol in wine if the density of ethanol is 0.785 g/mL?
A
1.05 M
B
3.50 M
C
0.85 M
D
2.30 M
Guida verificata passo dopo passo1
Start by understanding that 13.5% v/v means there are 13.5 mL of ethanol in every 100 mL of wine.
Calculate the mass of ethanol using its volume and density. Use the formula: mass = volume × density. Here, volume = 13.5 mL and density = 0.785 g/mL.
Convert the mass of ethanol to moles. Use the molar mass of ethanol (C₂H₅OH), which is approximately 46.08 g/mol. Use the formula: moles = mass / molar mass.
Determine the volume of the solution in liters. Since the percentage is based on 100 mL of wine, convert this to liters by dividing by 1000.
Calculate the molarity of ethanol by dividing the number of moles of ethanol by the volume of the solution in liters. Use the formula: Molarity (M) = moles of solute / liters of solution.
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