Enter the K sp expression for C 2 D 3 in terms of the molar solubility x.

Hello everyone today we are being asked to identify the compound that has the smallest Ks. P. Value from the following general ionic compounds and their abilities in pure water. So first we're gonna start out with A. And A. Has M. Two X. We're going to say it's mostly ability is 3.52 times 10 to the negative fourth moller. First you want to write out what this would dissolve into. So if you have em two X we can say this is a solid and then it's going to form two M plus ions as well as one X two minus Aquarius ions as well. And so when we set up our K. Sp expression it's always going to be products Overreactions but we're not worried about solids. Just the acquis forms. So we're going to say two X. Two X. Represents the M. There's two of them and we don't know the concentration of em. So we're going to leave as X. And since we have a coefficient of two that will become our exponent. And then for X we simply have another X. When we simplify this we get four X cubed. And we can simply plug in our molars eligibility. So we have four times 3.52 times 10 to the negative fourth cubed. Which gives us 1. Times 10 to the -10. And so we're going to hold onto that while we solve for the other ones. And so for B we have M. X. Three which in the solid form will disassociate to form one M. Three plus ion in the form as well as three X minus ions in the aqueous form. And so we set up our K. S. P. Will say K. S. P. Is equal to we have X. For em and then X. We have three of those so we have three X. And since our coefficient is three we're going to go ahead and cube that just as we did before, we're going to combine this and that's gonna give us 27 X to the fourth. We plug in our K. S. P. And we get 27 times 2. times 10 to the negative fourth. We're gonna cue that And that gives us a total of 1.12 times 10 to the negative 13th. We're gonna hold on to that value as we saw for the last and final one. So we have M. X. Which in the solid form it's just going to simply dissolve into M plus and x minus ions in the quickest form. And so our K. S. P. Is really simple. It's just going to be X times X which will combine to form X squared. We set our K. S. P. Value, we plug in our more easily ability which is just 4.23 times to the negative fourth. And we square that. That gives us a value of 1.79 times 10 to the negative seventh. And so looking at these three values, we can note that B 1.21 point 12 times 10 to the negative 13th is the smallest k. S. P value. From these three problems, hope this helped until next time.

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18. Aqueous Equilibrium

Solubility Product Constant: Ksp

General Chemistry

18. Aqueous Equilibrium

Solubility Product Constant: Ksp

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Enter the K_sp expression for C₂D₃ in terms of the molar solubility x.

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Enter the Ksp expression for C2D3 in terms of the molar solubility x.

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Set di pratica su Solubility Product Constant: Ksp

Enter the K_sp expression for C₂D₃ in terms of the molar solubility x.