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Question

When 2.50×$$10^{–3}$$ mol of CuCl are added to 450.0 mL of a 0.250 M KCN solution, a complex ion with the formula [Cu(CN)_{2}]^{–} is formed. Kf for the complex ion is 1.00×$$10^{16}. $$What is the fraction of uncomplexed $$Cu^{+}$$ ions in the solution?

Accepted Answer

Fraction of uncomplexed Cu+ ions = 1.75×$$10^{–15}$$

Answer

Fraction of uncomplexed Cu+ ions = 5.11×$$10^{–15}$$

Answer

Fraction of uncomplexed Cu+ ions = 3.12×$$10^{–13}$$

Answer

Fraction of uncomplexed Cu+ ions = 4.15×$$10^{–14}$$

When 2.50×10–3 mol of CuCl are added to 450.0 mL of a 0.250 M KCN solution, a complex ion with the formula [Cu(CN)2]– is formed. Kf for the complex ion is 1.00×1016. What is the fraction of uncomplexed Cu+ ions in the solution?

When 2.50×10^–3 mol of CuCl are added to 450.0 mL of a 0.250 M KCN solution, a complex ion with the formula [Cu(CN)₂]^– is formed. Kf for the complex ion is 1.00×10¹⁶. What is the fraction of uncomplexed Cu⁺ ions in the solution?