The solubility product for Zn1OH22 is 3.0 * 10-16. The formation constant for the hydroxo complex, Zn1OH242 - , is 4.6 * 1017. What concentration of OH- is required to dissolve 0.015 mol of Zn1OH22 in a liter of solution?
Ch.17 - Additional Aspects of Aqueous Equilibria
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Brown 14th Edition
Ch.17 - Additional Aspects of Aqueous Equilibria
Problema 109a
Brown 14th Edition
Ch.17 - Additional Aspects of Aqueous Equilibria
Problema 109aCapitolo 17, Problema 109a
The value of Ksp for Cd(OH)2 is 2.5 × 10-14. (a) What is the molar solubility of Cd(OH)2?
Guida verificata passo dopo passo1
Identify the dissolution equation for Cd(OH)2: Cd(OH)2(s) ⇌ Cd2+(aq) + 2OH-(aq).
Write the expression for the solubility product constant (Ksp): Ksp = [Cd2+][OH-]2.
Let the molar solubility of Cd(OH)2 be 's'. Then, [Cd2+] = s and [OH-] = 2s.
Substitute the expressions for the ion concentrations into the Ksp expression: Ksp = (s)(2s)2 = 4s3.
Set the Ksp expression equal to the given Ksp value and solve for 's': 4s3 = 2.5 × 10-14.

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Solubility Product Constant (Ksp)
The solubility product constant (Ksp) is an equilibrium constant that applies to the solubility of sparingly soluble ionic compounds. It is defined as the product of the molar concentrations of the ions, each raised to the power of their coefficients in the balanced equation. For Cd(OH)2, Ksp = [Cd^2+][OH^-]^2, which helps determine how much of the compound can dissolve in water.
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Solubility Product Constant
Molar Solubility
Molar solubility refers to the maximum concentration of a solute that can dissolve in a given volume of solvent at equilibrium. It is typically expressed in moles per liter (mol/L). In the case of Cd(OH)2, calculating the molar solubility involves determining the concentration of Cd^2+ and OH^- ions that can exist in solution when the compound is at its saturation point.
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Molar Solubility Example
Stoichiometry of Dissolution
The stoichiometry of dissolution describes the ratio in which ions are produced when a compound dissolves. For Cd(OH)2, the dissolution can be represented as Cd(OH)2(s) ⇌ Cd^2+(aq) + 2OH^-(aq). This indicates that one mole of Cd(OH)2 produces one mole of Cd^2+ and two moles of OH^-, which is essential for relating Ksp to molar solubility.
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Stoichiometry Concept
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