The Kb for methylamine (CH3NH2) at 25 °C is given in Appendix D. (d) What is the value of ΔG when [H+] = 6.7 × 10-9 M, [CH3NH3+] = 2.4 × 10-3 M, and [CH3NH2] = 0.098 M?
Ch.19 - Chemical Thermodynamics
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Capitolo 19, Problema 84a
The Kb for methylamine (CH3NH2) at 25 °C is given in Appendix D. (a) Write the chemical equation for the equilibrium that corresponds to Kb.
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Identify the base in the problem: Methylamine (CH_3NH_2) is a weak base.
Recall that the base dissociation constant, K_b, is related to the equilibrium of a base reacting with water.
Write the chemical equation for the reaction of methylamine with water: CH_3NH_2 + H_2O \(\rightleftharpoons\) CH_3NH_3^+ + OH^-.
Recognize that in this equilibrium, methylamine accepts a proton from water, forming the methylammonium ion (CH_3NH_3^+) and hydroxide ion (OH^-).
Ensure the equation is balanced and represents the equilibrium process for which K_b is defined.

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Equilibrium Constant (K_b)
The base dissociation constant, K_b, quantifies the strength of a base in solution. It is defined as the ratio of the concentration of the products to the concentration of the reactants at equilibrium for the reaction of a base with water. A higher K_b value indicates a stronger base, as it suggests a greater tendency to accept protons.
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Equilibrium Constant K
Chemical Equilibrium
Chemical equilibrium occurs when the rates of the forward and reverse reactions are equal, resulting in constant concentrations of reactants and products. In the context of a base like methylamine, this means that the formation of hydroxide ions and the conjugate acid reaches a stable state where their concentrations no longer change over time.
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Chemical Equilibrium Concepts
Methylamine as a Base
Methylamine (CH₃NH₂) is an organic compound that acts as a weak base in aqueous solution. When dissolved in water, it can accept a proton (H⁺) from water, leading to the formation of its conjugate acid (methylammonium ion, CH₃NH₃⁺) and hydroxide ions (OH⁻). This reaction is essential for writing the equilibrium expression for K_b.
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Base Example
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