Domanda del libro di testo
Write a balanced equation for each of the following reactions:
b. Upon heating, boric acid undergoes a condensation reaction to form tetraboric acid.
103
views
Ch.22 - Chemistry of the Nonmetals
Brown14th EditionChemistry: The Central ScienceISBN: 9780134414232
Non è quello che usi tu?Cambia libro di testoScegli un libro di testo diverso
TOC.tableOfContents
- Ch.1 - Introduction: Matter, Energy, and Measurement177
- Ch.2 - Atoms, Molecules, and Ions231
- Ch.3 - Chemical Reactions and Reaction Stoichiometry216
- Ch.4 - Reactions in Aqueous Solution189
- Ch.5 - Thermochemistry175
- Ch.6 - Electronic Structure of Atoms168
- Ch.7 - Periodic Properties of the Elements150
- Ch.8 - Basic Concepts of Chemical Bonding177
- Ch.9 - Molecular Geometry and Bonding Theories200
- Ch.10 - Gases179
- Ch.11 - Liquids and Intermolecular Forces113
- Ch.12 - Solids and Modern Materials154
- Ch.13 - Properties of Solutions157
- Ch.14 - Chemical Kinetics199
- Ch.15 - Chemical Equilibrium128
- Ch.16 - Acid-Base Equilibria164
- Ch.17 - Additional Aspects of Aqueous Equilibria163
- Ch.18 - Chemistry of the Environment105
- Ch.19 - Chemical Thermodynamics164
- Ch.20 - Electrochemistry171
- Ch.21 - Nuclear Chemistry122
- Ch.22 - Chemistry of the Nonmetals82
- Ch.23 - Transition Metals and Coordination Chemistry79
- Ch.24 - The Chemistry of Life: Organic and Biological Chemistry16
Brown14th EditionChemistry: The Central ScienceISBN: 9780134414232Non è quello che usi tu?Cambia libro di testo
Capitolo 22, Problema 78a
Write a balanced equation for each of the following reactions:
a. Diborane reacts with water to form boric acid and molecular hydrogen.
Guida verificata passo dopo passo1
Step 1: Write down the unbalanced chemical equation. Diborane (B2H6) reacts with water (H2O) to form boric acid (H3BO3) and molecular hydrogen (H2). So, the unbalanced equation is: B2H6 + H2O -> H3BO3 + H2.
Step 2: Balance the equation for the number of boron atoms first. There are 2 boron atoms on the left side and only 1 on the right side. So, we put a coefficient of 2 in front of H3BO3 on the right side: B2H6 + H2O -> 2H3BO3 + H2.
Step 3: Next, balance the equation for the number of hydrogen atoms. There are 6 hydrogen atoms on the left side and 8 on the right side (6 from 2H3BO3 and 2 from H2). So, we put a coefficient of 4 in front of H2O on the left side: B2H6 + 4H2O -> 2H3BO3 + H2.
Step 4: Finally, balance the equation for the number of hydrogen atoms again. Now, there are 14 hydrogen atoms on the left side (6 from B2H6 and 8 from 4H2O) and 8 on the right side. So, we put a coefficient of 3 in front of H2 on the right side: B2H6 + 4H2O -> 2H3BO3 + 3H2.
Step 5: Check the equation to make sure it is balanced. There should be the same number of each type of atom on both sides of the equation. In this case, there are 2 boron atoms, 14 hydrogen atoms, and 4 oxygen atoms on both sides, so the equation is balanced.
Risposta video verificata per un problema simile:
Questa soluzione video è stata consigliata dai nostri tutor come utile per risolvere questo problema.
Durata del video:
3mConcetti chiave
Ecco i concetti essenziali che devi comprendere per rispondere correttamente alla domanda.
Balancing Chemical Equations
Balancing chemical equations involves ensuring that the number of atoms of each element is the same on both sides of the equation. This is based on the law of conservation of mass, which states that matter cannot be created or destroyed in a chemical reaction. To balance an equation, coefficients are adjusted in front of the chemical formulas to achieve equal atom counts.
Video consigliato:
Percorso guidato
01:32
Balancing Chemical Equations
Diborane (B2H6) and Its Reactivity
Diborane (B2H6) is a compound consisting of boron and hydrogen, known for its unique bonding and reactivity. It reacts with water in a hydrolysis reaction, producing boric acid (H3BO3) and hydrogen gas (H2). Understanding the structure and reactivity of diborane is crucial for predicting the products of its reactions.
Video consigliato:
Percorso guidato
01:34The greater the interaction between the metal and its ligands then the greater the energy of its d orbitals
Products of Hydrolysis Reactions
In hydrolysis reactions, a compound reacts with water, leading to the formation of new products. In the case of diborane reacting with water, the products are boric acid and hydrogen gas. Recognizing the typical products of hydrolysis helps in writing balanced equations and understanding the nature of the reaction.
Video consigliato:
Percorso guidato
01:30Production of Hydrogen Example