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Ch.6 - Electronic Structure of Atoms
Brown - Chemistry: The Central Science 14th Edition
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Tutti i libri di testoBrown 14th EditionCh.6 - Electronic Structure of AtomsProblema 26c
Capitolo 6, Problema 26c

(c) The laser pointer emits light because electrons in the material are excited (by a battery) from their ground state to an upper excited state. When the electrons return to the ground state, they lose the excess energy in the form of 532-nm photons. What is the energy gap between the ground state and excited state in the laser material?

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Identify the wavelength of the photon emitted, which is given as 532 nm.
Convert the wavelength from nanometers to meters by multiplying by \(10^{-9}\).
Use the equation for the energy of a photon, \(E = \frac{hc}{\lambda}\), where \(h\) is Planck's constant (\(6.626 \times 10^{-34}\) J·s), \(c\) is the speed of light (\(3.00 \times 10^8\) m/s), and \(\lambda\) is the wavelength in meters.
Substitute the values of \(h\), \(c\), and \(\lambda\) into the equation to calculate the energy \(E\) in joules.
The calculated energy represents the energy gap between the ground state and the excited state in the laser material.

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Energy Levels in Atoms

Atoms have quantized energy levels where electrons reside. The ground state is the lowest energy level, while excited states are higher energy levels. When electrons absorb energy, they can transition to these excited states. The difference in energy between these levels determines the energy of the photons emitted when electrons return to the ground state.
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Atom Structure

Photon Energy and Wavelength

The energy of a photon is inversely related to its wavelength, described by the equation E = hc/λ, where E is energy, h is Planck's constant, c is the speed of light, and λ is the wavelength. For the laser pointer emitting 532-nm photons, this relationship allows us to calculate the energy of the emitted photons, which corresponds to the energy gap between the excited and ground states.
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Calculating Energy Gaps

To find the energy gap between the ground state and excited state, one can use the energy of the emitted photon. By substituting the wavelength of the emitted light into the photon energy equation, we can determine the energy difference. This calculation is essential for understanding the transitions of electrons in the laser material and the efficiency of the laser process.
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