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Ch.14 - Chemical Kinetics
Brown - Chemistry: The Central Science 15th Edition
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Tutti i libri di testoBrown 15th EditionCh.14 - Chemical KineticsProblema 112c
Capitolo 14, Problema 112c

In a hydrocarbon solution, the gold compound (CH3)3AuPH3 decomposes into ethane (C2H6) and a different gold compound, (CH3)AuPH3. The following mechanism has been proposed for the decomposition of (CH3)3AuPH3:
Step 1: (CH3)3AuPH3 k1⇌k-1 (CH3)3Au + PH3 (fast)
Step 2: (CH3)3Au k2→ C2H6 + (CH3)Au (slow)
Step 3: (CH3)Au + PH3 k3→ (CH3)AuPH3 (fast)
(c) What is the molecularity of each of the elementary steps?

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1
Identify the molecularity of Step 1: (CH_3)_3AuPH_3 ⇌ (CH_3)_3Au + PH_3. Since one molecule of (CH_3)_3AuPH_3 is involved in the reaction, this step is unimolecular.
Identify the molecularity of Step 2: (CH_3)_3Au → C_2H_6 + (CH_3)Au. This step involves the decomposition of a single molecule of (CH_3)_3Au, making it unimolecular.
Identify the molecularity of Step 3: (CH_3)Au + PH_3 → (CH_3)AuPH_3. This step involves two reactant molecules, (CH_3)Au and PH_3, so it is bimolecular.
Summarize the molecularity: Step 1 is unimolecular, Step 2 is unimolecular, and Step 3 is bimolecular.
Understand that molecularity refers to the number of molecules coming together to react in an elementary step, and it is always a whole number.

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Molecularity

Molecularity refers to the number of reactant molecules involved in an elementary reaction step. It can be classified as unimolecular (one molecule), bimolecular (two molecules), or termolecular (three molecules). Understanding molecularity is crucial for determining the rate law of a reaction and predicting how changes in concentration affect the reaction rate.
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Molecular Polarity

Elementary Steps

Elementary steps are individual reactions that occur in a multi-step reaction mechanism. Each step represents a single molecular event, and the overall reaction is the sum of these steps. Analyzing elementary steps helps in understanding the pathway of the reaction and the role of intermediates, which are species formed during the reaction but not present in the final products.
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Reaction Mechanism Overview

Rate Determining Step

The rate determining step (RDS) is the slowest step in a reaction mechanism that dictates the overall reaction rate. It is crucial to identify the RDS because it has the highest activation energy and thus controls how quickly the reaction proceeds. In the provided mechanism, the slow step is where (CH₃)₃Au decomposes, making it essential for calculating the reaction kinetics.
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Rate Law Determination
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The following mechanism has been proposed for the gasphase reaction of chloroform 1CHCl32 and chlorine:

Step 1: Cl2(g) k1⇌ k-1 2 Cl(g) (fast)

Step 2: Cl(g) + CHCl3(g) k2→ HCl(g) + CCl3(g) (slow)

Step 3: Cl(g0 + CCl3(g) k3→ CCl4 (fast)

(e) What is the rate law predicted by this mechanism? (Hint: The overall reaction order is not an integer.)

Domanda del libro di testo

Platinum nanoparticles of diameter 2 nm are important catalysts in carbon monoxide oxidation to carbon dioxide. Platinum crystallizes in a face-centered cubic arrangement with an edge length of 3.924 Å. (b) Estimate how many platinum atoms are on the surface of a 2.0-nm Pt sphere, using the surface area of a sphere (4πr2) and assuming that the 'footprint' of one Pt atom can be estimated from its atomic diameter of 2.8 A .

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Domanda del libro di testo

In a hydrocarbon solution, the gold compound (CH3)3AuPH3 decomposes into ethane (C2H6) and a different gold compound, (CH3)AuPH3. The following mechanism has been proposed for the decomposition of (CH3)3AuPH3:

Step 1: (CH3)3AuPH3 k1⇌k-1 (CH3)3Au + PH3 (fast)

Step 2: (CH3)3Au k2→ C2H6 + (CH3)Au (slow)

Step 3: (CH3)Au + PH3 k3→ (CH3)AuPH3 (fast)

(a) What is the overall reaction?

(b) What are the intermediates in the mechanism?

Domanda del libro di testo

In a hydrocarbon solution, the gold compound (CH3)3AuPH3 decomposes into ethane (C2H6) and a different gold compound, (CH3)AuPH3. The following mechanism has been proposed for the decomposition of (CH3)3AuPH3:

Step 1: (CH3)3AuPH3 k1⇌k-1 (CH3)3Au + PH3 (fast)

Step 2: (CH3)3Au k2→ C2H6 + (CH3)Au (slow)

Step 3: (CH3)Au + PH3 k3→ (CH3)AuPH3 (fast)

(e) What is the rate law predicted by this mechanism?

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views
Domanda del libro di testo

In a hydrocarbon solution, the gold compound (CH3)3AuPH3 decomposes into ethane (C2H6) and a different gold compound, (CH3)AuPH3. The following mechanism has been proposed for the decomposition of (CH3)3AuPH3:

Step 1: (CH3)3AuPH3 k1⇌k-1 (CH3)3Au + PH3 (fast)

Step 2: (CH3)3Au k2→ C2H6 + (CH3)Au (slow)

Step 3: (CH3)Au + PH3 k3→ (CH3)AuPH3 (fast)

(f) What would be the effect on the reaction rate of adding PH3 to the solution of (CH3)3AuPH3?

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