Balance the following equations: d. AlCl3(𝑠)+Ca3N2(𝑠)⟶AlN(𝑠)+CaCl2(𝑠)

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Identify the number of each type of atom on both sides of the equation. For the reactants: AlCl_3 has 1 Al and 3 Cl, and Ca_3N_2 has 3 Ca and 2 N. For the products: AlN has 1 Al and 1 N, and CaCl_2 has 1 Ca and 2 Cl.

Start by balancing the metals. Balance the aluminum (Al) atoms first. Since there is 1 Al in AlCl_3 and 1 Al in AlN, they are already balanced.

Next, balance the calcium (Ca) atoms. There are 3 Ca atoms in Ca_3N_2, so you need 3 CaCl_2 to balance the Ca atoms on the product side.

Now, balance the nitrogen (N) atoms. There are 2 N atoms in Ca_3N_2, so you need 2 AlN to balance the N atoms on the product side.

Finally, balance the chlorine (Cl) atoms. You have 3 AlCl_3 providing 9 Cl atoms, and you need 3 CaCl_2 to provide 6 Cl atoms. Adjust the coefficients to ensure all atoms are balanced.

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Balancing chemical equations involves ensuring that the number of atoms for each element is the same on both sides of the equation. This is based on the law of conservation of mass, which states that matter cannot be created or destroyed in a chemical reaction. Coefficients are used to adjust the quantities of reactants and products to achieve balance.

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