Skip to main content
Ch.5 - Thermochemistry
Brown - Chemistry: The Central Science 15th Edition
Brown15th EditionChemistry: The Central ScienceISBN: 9780137542970Non è quello che usi tu?Cambia libro di testo
Capitolo 5, Problema 46c

At one time, a common means of forming small quantities of oxygen gas in the laboratory was to heat KClO3: 2 KClO3(s) → 2 KCl(s) + 3 O2(g) ΔH = -89.4 kJ c. Now consider the reverse reaction, in which KClO3 is formed from KCl and O2. What is Δ𝐻 for the formation of 19.1 g KClO3 from KCl and O2?

Guida verificata passo dopo passo
1
Identify the given reaction: 2 KClO_3(s) \(\rightarrow\) 2 KCl(s) + 3 O_2(g) with \(\Delta\) H = -89.4 \(\text{ kJ}\).
Recognize that the reverse reaction is being considered: 2 KCl(s) + 3 O_2(g) \(\rightarrow\) 2 KClO_3(s).
For the reverse reaction, the enthalpy change (\(\Delta\) H) will be the opposite sign of the forward reaction, so \(\Delta\) H = +89.4 \(\text{ kJ}\) for the formation of 2 moles of KClO_3.
Calculate the molar mass of KClO_3: K (39.10 g/mol) + Cl (35.45 g/mol) + 3 \(\times\) O (16.00 g/mol) = 122.55 g/mol.
Determine the \(\Delta\) H for the formation of 19.1 g of KClO_3 by using the ratio: \(\Delta\) H = \(\left\)(\(\frac{19.1 \text{ g}\)}{2 \(\times\) 122.55 \(\text{ g/mol}\)}\(\right\)) \(\times\) 89.4 \(\text{ kJ}\).

Risposta video verificata per un problema simile:

Questa soluzione video è stata consigliata dai nostri tutor come utile per risolvere questo problema.
Durata del video:
1m

Concetti chiave

Ecco i concetti essenziali che devi comprendere per rispondere correttamente alla domanda.

Thermochemistry

Thermochemistry is the study of the heat energy associated with chemical reactions and changes of state. It involves understanding how energy is absorbed or released during reactions, which is quantified as enthalpy change (ΔH). In this context, the ΔH value indicates whether a reaction is exothermic (releases heat) or endothermic (absorbs heat), which is crucial for calculating the energy changes in the formation of KClO3.
Video consigliato:

Stoichiometry

Stoichiometry is the branch of chemistry that deals with the quantitative relationships between the reactants and products in a chemical reaction. It allows chemists to calculate the amounts of substances consumed and produced in a reaction based on balanced chemical equations. In this question, stoichiometry is essential for determining how much KClO3 can be formed from a given mass of KCl and O2, using the coefficients from the balanced equation.
Video consigliato:
Percorso guidato
01:16
Stoichiometry Concept

Reverse Reactions and Hess's Law

Hess's Law states that the total enthalpy change for a reaction is the same, regardless of the number of steps taken to complete the reaction. This principle is particularly useful when considering reverse reactions, as the ΔH for the reverse process is equal in magnitude but opposite in sign to that of the forward reaction. In this case, calculating the ΔH for the formation of KClO3 from KCl and O2 requires applying Hess's Law to the given reaction.
Video consigliato:
Pratica correlata
Domanda del libro di testo

When solutions containing silver ions and chloride ions are mixed, silver chloride precipitates Ag+(aq) + Cl-(aq) → AgCl(s) H = -65.5 kJ (a) Calculate H for the production of 0.450 mol of AgCl by this reaction. (b) Calculate H for the production of 9.00 g of AgCl. (c) Calculate H when 9.25⨉10-4 mol of AgCl dissolves in water.

861
views
Domanda del libro di testo

At one time, a common means of forming small quantities of oxygen gas in the laboratory was to heat KClO3: 2 KClO3(s) → 2 KCl(s) + 3 O2(g) ΔH = -89.4 kJ For this reaction, calculate H for the formation of (a) 1.36 mol of O2

560
views
Domanda del libro di testo

At one time, a common means of forming small quantities of oxygen gas in the laboratory was to heat KClO3: 2 KClO3(s) → 2 KCl(s) + 3 O2(g) ΔH = -89.4 kJ For this reaction, calculate H for the formation of (b) 10.4 g of KCl.

423
views
Domanda del libro di testo

Consider the decomposition of liquid benzene, C6H6(l), to gaseous acetylene, C2H2(g): C6H6(l) → 3 C2H2(g) ΔH = +630 kJ (a) What is the enthalpy change for the reverse reaction?

803
views
Domanda del libro di testo

Consider the combustion of isopropanol, C3H7OH(l), which is the primary component of rubbing alcohol: C3H7OH(l) + 9/2 O2(g) → 3 CO2(g) + 4 H2O(l) ΔH = -2248 kJ (b) Balance the forward reaction with whole-number coefficients. What is ΔH for the reaction represented by this equation?

3
views
Domanda del libro di testo

Consider the combustion of isopropanol, C3H7OH(l), which is the primary component of rubbing alcohol: C3H7OH(l) + 9/2 O2(g) → 3 CO2(g) + 4 H2O(l) ΔH = -2248 kJ a. What is the enthalpy change for the reverse reaction?

3
views