Domanda del libro di testo
(a) Calculate the energy of a photon of electromagnetic radiation whose frequency is 2.94 × 1014 s-1.
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Ch.6 - Electronic Structure of Atoms
Brown15th EditionChemistry: The Central ScienceISBN: 9780137542970
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TOC.tableOfContents
- Ch.1 - Introduction: Matter, Energy, and Measurement146
- Ch.2 - Atoms, Molecules, and Ions200
- Ch.3 - Chemical Reactions and Reaction Stoichiometry176
- Ch.4 - Reactions in Aqueous Solution155
- Ch.5 - Thermochemistry126
- Ch.6 - Electronic Structure of Atoms131
- Ch.7 - Periodic Properties of the Elements126
- Ch.8 - Basic Concepts of Chemical Bonding123
- Ch.9 - Molecular Geometry and Bonding Theories143
- Ch.10 - Gases147
- Ch.11 - Liquids and Intermolecular Forces91
- Ch.12 - Solids and Modern Materials122
- Ch.13 - Properties of Solutions126
- Ch.14 - Chemical Kinetics174
- Ch.15 - Chemical Equilibrium101
- Ch.16 - Acid-Base Equilibria139
- Ch.17 - Additional Aspects of Aqueous Equilibria146
- Ch.18 - Chemistry of the Environment72
- Ch.19 - Chemical Thermodynamics129
- Ch.20 - Electrochemistry142
- Ch.21 - Nuclear Chemistry101
- Ch.22 - Chemistry of the Nonmetals68
- Ch.23 - Transition Metals and Coordination Chemistry66
- Ch.24 - The Chemistry of Life: Organic and Biological Chemistry10
Brown15th EditionChemistry: The Central ScienceISBN: 9780137542970Non è quello che usi tu?Cambia libro di testo
Capitolo 6, Problema 26a
(a) A green laser pointer emits light with a wavelength of 532 nm. What is the frequency of this light?
Guida verificata passo dopo passo1
Identify the relationship between wavelength and frequency using the equation: \( c = \lambda \nu \), where \( c \) is the speed of light (approximately \( 3.00 \times 10^8 \) m/s), \( \lambda \) is the wavelength, and \( \nu \) is the frequency.
Convert the given wavelength from nanometers to meters. Since 1 nm = \( 1 \times 10^{-9} \) m, multiply 532 nm by \( 1 \times 10^{-9} \) to convert it to meters.
Rearrange the equation \( c = \lambda \nu \) to solve for frequency \( \nu \): \( \nu = \frac{c}{\lambda} \).
Substitute the values for \( c \) and \( \lambda \) into the equation: \( \nu = \frac{3.00 \times 10^8 \text{ m/s}}{\lambda} \), where \( \lambda \) is the wavelength in meters.
Calculate the frequency \( \nu \) using the substituted values to find the frequency of the green laser light.
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Wavelength and Frequency Relationship
The relationship between wavelength and frequency is described by the equation c = λν, where c is the speed of light (approximately 3.00 x 10^8 m/s), λ is the wavelength in meters, and ν is the frequency in hertz. This equation shows that as the wavelength increases, the frequency decreases, and vice versa. Understanding this relationship is crucial for converting between these two properties of light.
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Percorso guidato
00:31
Frequency-Wavelength Relationship
Units of Measurement
In physics and chemistry, it is essential to use consistent units when performing calculations. Wavelength is often measured in nanometers (nm), where 1 nm = 1 x 10^-9 meters. Frequency is measured in hertz (Hz), which is equivalent to cycles per second. Converting units correctly ensures accurate calculations and results.
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02:52Units of Radiation Measurement
Electromagnetic Spectrum
The electromagnetic spectrum encompasses all types of electromagnetic radiation, including visible light, which ranges from approximately 400 nm (violet) to 700 nm (red). A wavelength of 532 nm falls within the visible spectrum, specifically in the green region. Understanding where a wavelength lies in the spectrum helps in identifying its properties and applications.
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02:53Electromagnetic Spectrum
Pratica correlata
Domanda del libro di testo
(b) Calculate the energy of a photon of radiation whose wavelength is 413 nm.
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Domanda del libro di testo
If human height were quantized in 1-foot increments, what would happen to the height of a child as she grew up?
a. The child’s height would never change.
b. The child’s height would continuously get greater.
c. The child’s height would increase in “jumps” of 1 foot at a time.
d. The child’s height would increase in jumps of 6 inches.
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Domanda del libro di testo
(c) The laser pointer emits light because electrons in the material are excited (by a battery) from their ground state to an upper excited state. When the electrons return to the ground state, they lose the excess energy in the form of 532-nm photons. What is the energy gap between the ground state and excited state in the laser material?
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Domanda del libro di testo
(b) What is the energy of one of these photons?
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