Domanda del libro di testo
Chlorine reacts with oxygen to form Cl2O7. (c) Would you expect Cl2O7 to be more reactive toward H+1aq2 or OH-1aq2?
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Ch.7 - Periodic Properties of the Elements
Brown15th EditionChemistry: The Central ScienceISBN: 9780137542970
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TOC.tableOfContents
- Ch.1 - Introduction: Matter, Energy, and Measurement146
- Ch.2 - Atoms, Molecules, and Ions200
- Ch.3 - Chemical Reactions and Reaction Stoichiometry176
- Ch.4 - Reactions in Aqueous Solution155
- Ch.5 - Thermochemistry126
- Ch.6 - Electronic Structure of Atoms131
- Ch.7 - Periodic Properties of the Elements126
- Ch.8 - Basic Concepts of Chemical Bonding123
- Ch.9 - Molecular Geometry and Bonding Theories143
- Ch.10 - Gases147
- Ch.11 - Liquids and Intermolecular Forces91
- Ch.12 - Solids and Modern Materials122
- Ch.13 - Properties of Solutions126
- Ch.14 - Chemical Kinetics174
- Ch.15 - Chemical Equilibrium101
- Ch.16 - Acid-Base Equilibria139
- Ch.17 - Additional Aspects of Aqueous Equilibria146
- Ch.18 - Chemistry of the Environment72
- Ch.19 - Chemical Thermodynamics129
- Ch.20 - Electrochemistry142
- Ch.21 - Nuclear Chemistry101
- Ch.22 - Chemistry of the Nonmetals68
- Ch.23 - Transition Metals and Coordination Chemistry66
- Ch.24 - The Chemistry of Life: Organic and Biological Chemistry10
Brown15th EditionChemistry: The Central ScienceISBN: 9780137542970Non è quello che usi tu?Cambia libro di testo
Capitolo 7, Problema 63b
Chlorine reacts with oxygen to form Cl2O7. (b) Write a balanced equation for the formation of Cl2O71l2 from the elements.
Guida verificata passo dopo passo1
Step 1: Identify the reactants and the product. In this case, the reactants are Chlorine (Cl2) and Oxygen (O2), and the product is Cl2O7.
Step 2: Write the unbalanced chemical equation. This is done by writing the reactants on the left side of the equation and the product on the right side of the equation. The unbalanced equation would be: Cl2 + O2 -> Cl2O7.
Step 3: Balance the equation. Start by balancing the Chlorine atoms. In this case, there are 2 Chlorine atoms on both sides of the equation, so they are already balanced.
Step 4: Next, balance the Oxygen atoms. There are 2 Oxygen atoms on the left side of the equation and 7 on the right side. To balance the Oxygen atoms, you can place a coefficient of 7/2 in front of the O2 on the left side of the equation. This gives: Cl2 + 7/2 O2 -> Cl2O7.
Step 5: However, in chemistry, we generally avoid using fractional coefficients. To get rid of the fraction, multiply every coefficient by 2. This gives the final balanced equation: 2 Cl2 + 7 O2 -> 2 Cl2O7.
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Balancing Chemical Equations
Balancing chemical equations is essential to ensure that the number of atoms of each element is the same on both sides of the equation. This reflects the law of conservation of mass, which states that matter cannot be created or destroyed in a chemical reaction. To balance an equation, coefficients are adjusted in front of the chemical formulas to achieve equal atom counts.
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01:32
Balancing Chemical Equations
Stoichiometry
Stoichiometry involves the calculation of reactants and products in chemical reactions based on their molar ratios. It allows chemists to predict the amounts of substances consumed and produced in a reaction. Understanding stoichiometry is crucial for writing balanced equations and for practical applications in laboratory settings.
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01:16Stoichiometry Concept
Formation Reactions
A formation reaction is a specific type of chemical reaction where elements combine to form a compound. In the context of the question, the formation of Cl2O7 from chlorine and oxygen involves identifying the correct stoichiometric coefficients for each element. This concept is fundamental in understanding how compounds are synthesized from their elemental forms.
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02:34Enthalpy of Formation
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