Domanda del libro di testo
A sample that weighs 107.75 g is a mixture of 30% helium atoms and 70% krypton atoms. How many particles are present in the sample?
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Ch.3 - Mass Relationships in Chemical Reactions
McMurry8th EditionChemistryISBN: 9781292336145
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TOC.tableOfContents
- Ch.1 - Chemical Tools: Experimentation & Measurement170
- Ch.2 - Atoms, Molecules & Ions160
- Ch.3 - Mass Relationships in Chemical Reactions169
- Ch.4 - Reactions in Aqueous Solution199
- Ch.5 - Periodicity & Electronic Structure of Atoms102
- Ch.6 - Ionic Compounds: Periodic Trends and Bonding Theory92
- Ch.7 - Covalent Bonding and Electron-Dot Structures61
- Ch.8 - Covalent Compounds: Bonding Theories and Molecular Structure59
- Ch.9 - Thermochemistry: Chemical Energy122
- Ch.10 - Gases: Their Properties & Behavior155
- Ch.11 - Liquids & Phase Changes54
- Ch.12 - Solids and Solid-State Materials73
- Ch.13 - Solutions & Their Properties120
- Ch.14 - Chemical Kinetics98
- Ch.15 - Chemical Equilibrium125
- Ch.16 - Aqueous Equilibria: Acids & Bases110
- Ch.17 - Applications of Aqueous Equilibria147
- Ch.18 - Thermodynamics: Entropy, Free Energy & Equilibrium86
- Ch.19 - Electrochemistry154
- Ch.20 - Nuclear Chemistry96
- Ch.21 - Transition Elements and Coordination Chemistry156
- Ch.22 - The Main Group Elements187
- Ch.23 - Organic and Biological Chemistry51
Capitolo 3, Problema 60
Titanium metal is obtained from the mineral rutile, TiO2. How many kilograms of rutile are needed to produce 100.0 kg of Ti?
Guida verificata passo dopo passo1
Identify the chemical reaction involved in obtaining titanium from rutile: \( \text{TiO}_2 \rightarrow \text{Ti} \).
Determine the molar masses of \( \text{TiO}_2 \) and \( \text{Ti} \) using the periodic table: \( \text{TiO}_2 \) has a molar mass of approximately 79.87 g/mol (Ti: 47.87 g/mol, O: 16.00 g/mol each).
Calculate the moles of titanium needed: \( \text{moles of Ti} = \frac{100.0 \text{ kg of Ti}}{47.87 \text{ g/mol}} \).
Use the stoichiometry of the reaction to find the moles of \( \text{TiO}_2 \) required: Since the reaction is \( 1:1 \), the moles of \( \text{TiO}_2 \) needed are equal to the moles of \( \text{Ti} \).
Convert the moles of \( \text{TiO}_2 \) to kilograms: \( \text{mass of TiO}_2 = \text{moles of TiO}_2 \times 79.87 \text{ g/mol} \) and convert grams to kilograms.
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Stoichiometry
Stoichiometry is the branch of chemistry that deals with the quantitative relationships between the reactants and products in a chemical reaction. It allows us to calculate how much of a substance is needed or produced based on the balanced chemical equation. In this case, understanding the stoichiometric ratios between titanium (Ti) and rutile (TiO2) is essential for determining the amount of rutile required to produce a specific mass of titanium.
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Percorso guidato
01:16
Stoichiometry Concept
Molar Mass
Molar mass is the mass of one mole of a substance, typically expressed in grams per mole (g/mol). It is crucial for converting between the mass of a substance and the number of moles, which is necessary for stoichiometric calculations. For this question, knowing the molar masses of titanium (Ti) and rutile (TiO2) will enable the calculation of how many kilograms of rutile are needed to yield 100.0 kg of titanium.
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Percorso guidato
02:11Molar Mass Concept
Chemical Composition
Chemical composition refers to the types and amounts of elements that make up a compound. In the case of rutile (TiO2), it consists of titanium and oxygen in a specific ratio. Understanding the composition of rutile is important for determining how much titanium can be extracted from a given mass of rutile, which directly impacts the stoichiometric calculations needed to answer the question.
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Percorso guidato
04:19Matter Composition
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Iron metal can be produced from the mineral hematite, Fe2O3, by reaction with carbon. How many kilograms of iron are present in 105 kg of hematite?
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In the preparation of iron from hematite, Fe2O3 reacts with carbon:
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A sample that weighs 25.12 g contains 6.022⨉1023 particles. If 25.00% of the total number of particles are argon atoms and 75.00% are another element, what is the chemical identity of the other constituent?
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