Determine whether or not each nuclide is likely to be stable. State your reasons. a. Ti-48 b. Cr-63 c. Sn-102 d. Y-88

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To determine the stability of a nuclide, consider the neutron-to-proton (N/Z) ratio. A stable nuclide typically has an N/Z ratio close to 1 for lighter elements and slightly higher for heavier elements.

For Ti-48: Titanium (Ti) has an atomic number of 22, meaning it has 22 protons. Ti-48 has 48 - 22 = 26 neutrons. Calculate the N/Z ratio: \( \frac{26}{22} \). Compare this ratio to the typical stable range for elements around titanium.

For Cr-63: Chromium (Cr) has an atomic number of 24, meaning it has 24 protons. Cr-63 has 63 - 24 = 39 neutrons. Calculate the N/Z ratio: \( \frac{39}{24} \). Check if this ratio falls within the stable range for elements around chromium.

For Sn-102: Tin (Sn) has an atomic number of 50, meaning it has 50 protons. Sn-102 has 102 - 50 = 52 neutrons. Calculate the N/Z ratio: \( \frac{52}{50} \). Determine if this ratio is typical for stable isotopes of tin.

For Y-88: Yttrium (Y) has an atomic number of 39, meaning it has 39 protons. Y-88 has 88 - 39 = 49 neutrons. Calculate the N/Z ratio: \( \frac{49}{39} \). Evaluate if this ratio is within the stable range for yttrium isotopes.

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