Domanda del libro di testo
Write a nuclear equation for the indicated decay of each nuclide. e. Cr-51 (electron capture)
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Ch.21 - Radioactivity & Nuclear Chemistry
Tro5th EditionChemistry: A Molecular ApproachISBN: 9780134874371
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TOC.tableOfContents
- Ch.1 - Matter, Measurement & Problem Solving117
- Ch.2 - Atoms & Elements106
- Ch.3 - Molecules and Compounds128
- Ch.4 - Chemical Reactions and Chemical Quantities56
- Ch.5 - Introduction to Solutions and Aqueous Solutions84
- Ch.6 - Gases112
- Ch.7 - Thermochemistry96
- Ch.8 - The Quantum-Mechanical Model of the Atom60
- Ch.9 - Periodic Properties of the Elements86
- Ch.10 - Chemical Bonding I: The Lewis Model91
- Ch.11 - Chemical Bonding II: Molecular Shapes, VSEPR & MO Theory85
- Ch.12 - Liquids, Solids & Intermolecular Forces51
- Ch.13 - Solids & Modern Materials48
- Ch.14 - Solutions93
- Ch.15 - Chemical Kinetics114
- Ch.16 - Chemical Equilibrium68
- Ch.17 - Acids and Bases137
- Ch.18 - Aqueous Ionic Equilibrium154
- Ch.19 - Free Energy & Thermodynamics91
- Ch.20 - Electrochemistry105
- Ch.21 - Radioactivity & Nuclear Chemistry74
- Ch.22 - Organic Chemistry141
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Capitolo 21, Problema 31a
Write a nuclear equation for the indicated decay of each nuclide. a. U-234 (alpha) b. Th-230 (alpha)
Guida verificata passo dopo passo1
Identify the type of decay: Alpha decay involves the emission of an alpha particle, which is a helium nucleus \( ^4_2\text{He} \).
Write the general form of an alpha decay equation: \( ^A_Z\text{X} \rightarrow ^{A-4}_{Z-2}\text{Y} + ^4_2\text{He} \).
Determine the initial nuclide: The problem states U-234, which is uranium with a mass number of 234 and an atomic number of 92, so \( ^{234}_{92}\text{U} \).
Apply the alpha decay equation to U-234: \( ^{234}_{92}\text{U} \rightarrow ^{230}_{90}\text{Th} + ^4_2\text{He} \).
Verify the conservation of mass and atomic numbers: Ensure that the sum of mass numbers and atomic numbers on both sides of the equation are equal.
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Nuclear Decay
Nuclear decay is the process by which an unstable atomic nucleus loses energy by emitting radiation. This can occur in various forms, including alpha decay, beta decay, and gamma decay. In alpha decay, the nucleus emits an alpha particle, which consists of two protons and two neutrons, resulting in a new element with a lower atomic number.
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03:53
Alpha Decay
Alpha Particle
An alpha particle is a type of ionizing radiation ejected from the nucleus during alpha decay. It is composed of two protons and two neutrons, making it identical to a helium nucleus. The emission of an alpha particle decreases the atomic number of the original nuclide by two and the mass number by four, leading to the formation of a different element.
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02:48Characteristics of Alpha Particles
Nuclear Equation
A nuclear equation represents the transformation of one nuclide into another during a nuclear reaction. It includes the symbols for the reactants and products, along with their respective atomic numbers and mass numbers. For alpha decay, the equation typically shows the original nuclide, the emitted alpha particle, and the resulting nuclide, ensuring that both mass and charge are conserved.
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02:06Nuclear Binding Energy