Domanda del libro di testo
A certain substance X decomposes. Fifty percent of X remains after 100 minutes. How much X remains after 200 minutes if the reaction order with respect to X is (c) second order?
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Ch.15 - Chemical Kinetics
Tro6th EditionChemistry: A Molecular ApproachISBN: 9780137832217
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TOC.tableOfContents
- Ch.1 - Matter, Measurement & Problem Solving118
- Ch.2 - Atoms & Elements106
- Ch.3 - Molecules and Compounds131
- Ch.4 - Chemical Reactions and Chemical Quantities56
- Ch.5 - Introduction to Solutions and Aqueous Solutions82
- Ch.6 - Gases114
- Ch.7 - Thermochemistry96
- Ch.8 - The Quantum-Mechanical Model of the Atom60
- Ch.9 - Periodic Properties of the Elements90
- Ch.10 - Chemical Bonding I: The Lewis Model89
- Ch.11 - Chemical Bonding II: Molecular Shapes, VSEPR & MO Theory85
- Ch.12 - Liquids, Solids & Intermolecular Forces51
- Ch.13 - Solids & Modern Materials47
- Ch.14 - Solutions90
- Ch.15 - Chemical Kinetics115
- Ch.16 - Chemical Equilibrium68
- Ch.17 - Acids and Bases136
- Ch.18 - Aqueous Ionic Equilibrium153
- Ch.19 - Free Energy & Thermodynamics93
- Ch.20 - Electrochemistry106
- Ch.21 - Radioactivity & Nuclear Chemistry74
- Ch.22 - Organic Chemistry140
Tro6th EditionChemistry: A Molecular ApproachISBN: 9780137832217Non è quello che usi tu?Cambia libro di testo
Capitolo 15, Problema 116
The half-life for radioactive decay (a first-order process) of plutonium- 239 is 24,000 years. How many years does it take for one mole of this radioactive material to decay until just one atom remains?
Guida verificata passo dopo passo1
Identify the formula for first-order decay: \( N = N_0 e^{-kt} \), where \( N \) is the remaining quantity, \( N_0 \) is the initial quantity, \( k \) is the rate constant, and \( t \) is time.
Determine the initial quantity \( N_0 \) in terms of atoms. Since we start with one mole, use Avogadro's number \( 6.022 \times 10^{23} \) atoms/mole.
Set \( N = 1 \) atom, as we want to find the time when only one atom remains.
Calculate the rate constant \( k \) using the half-life formula for first-order reactions: \( k = \frac{0.693}{\text{half-life}} \). Substitute the given half-life of 24,000 years.
Rearrange the decay formula to solve for \( t \): \( t = \frac{\ln(N_0/N)}{k} \). Substitute the values for \( N_0 \), \( N \), and \( k \) to find \( t \).
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Half-Life
Half-life is the time required for half of the radioactive nuclei in a sample to decay. For first-order reactions, this is a constant value that characterizes the decay rate of the substance. In the case of plutonium-239, its half-life is 24,000 years, meaning after this period, half of the original amount will remain.
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Percorso guidato
02:17
Zero-Order Half-life
First-Order Kinetics
First-order kinetics refers to a reaction rate that is directly proportional to the concentration of one reactant. In radioactive decay, the rate at which a substance decays is proportional to the amount of the substance present. This means that as the quantity decreases, the rate of decay also decreases, leading to an exponential decay pattern.
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02:29First-Order Reactions
Exponential Decay
Exponential decay describes the process by which a quantity decreases at a rate proportional to its current value. In radioactive decay, the amount of substance remaining can be calculated using the formula N(t) = N0 * e^(-kt), where N0 is the initial quantity, k is the decay constant, and t is time. This concept is crucial for determining how long it takes for a substance to decay to a specific amount, such as one atom.
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03:01Beta Decay