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Ch.2 - Atoms & Elements
Tro - Chemistry: A Molecular Approach 6th Edition
Tro6th EditionChemistry: A Molecular ApproachISBN: 9780137832217Non è quello che usi tu?Cambia libro di testo
Capitolo 2, Problema 36

The mass ratio of sodium to fluorine in sodium fluoride is 1.21:1. A sample of sodium fluoride produces 45.1 g of sodium upon decomposition. How much fluorine (in grams) forms?

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Identify the given mass ratio of sodium to fluorine in sodium fluoride, which is 1.21:1.
Understand that this ratio means for every 1.21 grams of sodium, there is 1 gram of fluorine.
Given that the sample produces 45.1 grams of sodium, set up a proportion to find the mass of fluorine: \( \frac{\text{mass of sodium}}{\text{mass of fluorine}} = \frac{1.21}{1} \).
Substitute the given mass of sodium into the proportion: \( \frac{45.1}{x} = \frac{1.21}{1} \), where \( x \) is the mass of fluorine.
Solve the proportion for \( x \) to find the mass of fluorine.

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Stoichiometry

Stoichiometry is the branch of chemistry that deals with the quantitative relationships between the reactants and products in a chemical reaction. It allows chemists to predict the amounts of substances consumed and produced in a reaction based on balanced chemical equations. Understanding stoichiometry is essential for solving problems involving mass ratios and conversions between different substances.
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Molar Mass

Molar mass is the mass of one mole of a substance, typically expressed in grams per mole (g/mol). It is calculated by summing the atomic masses of all the atoms in a molecule. In the context of sodium fluoride (NaF), knowing the molar masses of sodium (Na) and fluorine (F) is crucial for determining the mass of fluorine produced when a specific mass of sodium is decomposed.
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Mass Ratio

The mass ratio is a comparison of the mass of one substance to the mass of another substance in a compound. In sodium fluoride, the mass ratio of sodium to fluorine is given as 1.21:1, indicating that for every 1.21 grams of sodium, there is 1 gram of fluorine. This ratio is vital for calculating the amount of fluorine produced from a known mass of sodium, as it provides a direct relationship between the two elements.
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