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Ch.3 - Molecules and Compounds
Tro - Chemistry: A Molecular Approach 6th Edition
Tro6th EditionChemistry: A Molecular ApproachISBN: 9780137832217Non è quello che usi tu?Cambia libro di testo
Tutti i libri di testoTro 6th EditionCh.3 - Molecules and CompoundsProblema 48b
Capitolo 3, Problema 48b

Write the formula for each ionic compound. b. copper(I) iodate c. lead(II) chromate e. potassium hydroxide

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Identify the ions involved in the compound. Copper(I) indicates the copper ion with a +1 charge, written as \( \text{Cu}^+ \). Iodate is a polyatomic ion with the formula \( \text{IO}_3^- \).
Determine the charges of the ions. Copper(I) has a charge of +1, and iodate has a charge of -1.
Balance the charges to ensure the compound is neutral. Since both ions have charges of +1 and -1, they balance each other out in a 1:1 ratio.
Write the formula by combining the ions in the ratio determined. Since the charges are balanced in a 1:1 ratio, the formula is \( \text{CuIO}_3 \).
Double-check the formula to ensure that the charges are balanced and the compound is neutral.

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Ionic Compounds

Ionic compounds are formed when atoms transfer electrons, resulting in the formation of positively charged cations and negatively charged anions. These oppositely charged ions attract each other, creating a stable compound. The overall charge of the compound must be neutral, which is achieved by balancing the charges of the constituent ions.
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Ionic Compounds Naming

Copper(I) Ion

Copper(I) refers to the copper ion with a +1 charge, denoted as Cu⁺. This indicates that copper has lost one electron, resulting in a cation. Understanding the oxidation state of copper is crucial for determining the correct formula of the ionic compound it forms with other ions, such as iodate.
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Exceptions (I)

Iodate Ion

The iodate ion is a polyatomic ion with the formula IO₃⁻, carrying a -1 charge. It consists of one iodine atom covalently bonded to three oxygen atoms. When forming ionic compounds, the charge of the iodate ion must be balanced with the charge of the cation, in this case, copper(I), to ensure the overall neutrality of the compound.
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Ion Formation
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