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In B-form DNA, the diameter of the double helix is about , and the rise per base pair along the helix axis is about . Approximately how many times longer (per base pair) is DNA than it is wide?
A
times
B
times
C
times
D
times
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1
Identify the given dimensions of B-form DNA: the diameter (width) is approximately 2 nm, and the rise per base pair (length per base pair) is approximately 0.34 nm.
Understand that the question asks for how many times longer the DNA is per base pair compared to its width, which means calculating the ratio of the length per base pair to the diameter.
Set up the ratio as: \(\text{Ratio} = \frac{\text{length per base pair}}{\text{diameter}}\).
Substitute the given values into the ratio: \(\text{Ratio} = \frac{0.34\ \text{nm}}{2\ \text{nm}}\).
Simplify the ratio to find how many times longer the DNA is per base pair than it is wide.