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Following the Law of Conservation of Mass, predict the minimum amount of nitrogen that will react with 50.0 grams of hydrogen to produce 92.5 grams of ammonia.
Nitrogen + Hydrogen → Ammonia
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5. Classification & Balancing of Chemical Reactions
Law of Conservation of Mass
Scelta multipla
Predict the amount of oxygen gas that will remain after the reaction of 112.6 grams of calcium with 24.0 grams of oxygen.
A
8.5 g
B
11.0 g
C
18.0 g
D
24.0 g
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Write the balanced chemical equation for the reaction: 2Ca + O2 -> 2CaO.
Calculate the moles of calcium (Ca) using its molar mass (40.08 g/mol): moles of Ca = 112.6 g / 40.08 g/mol.
Calculate the moles of oxygen (O2) using its molar mass (32.00 g/mol): moles of O2 = 24.0 g / 32.00 g/mol.
Determine the limiting reactant by comparing the mole ratio from the balanced equation. The reaction requires 1 mole of O2 for every 2 moles of Ca.
Calculate the amount of oxygen gas that remains unreacted by subtracting the moles of O2 that reacted from the initial moles of O2, then convert the remaining moles back to grams using the molar mass of O2.
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