Write the balanced chemical equations for the (1) reaction of each of the following amines with water and (2) neutralization with HBr:
b. propylamine

Guida verificata passo dopo passo

Step 1: Understand the problem. Propylamine (C₃H₇NH₂) is a primary amine. When it reacts with water, it acts as a weak base, accepting a proton (H⁺) from water to form its conjugate acid and hydroxide ions (OH⁻). In the neutralization reaction with HBr, the amine reacts with the acid to form an ammonium salt.

Step 2: Write the reaction of propylamine with water. The general reaction for an amine (RNH₂) with water is: RNH₂ + H₂O ⇌ RNH₃⁺ + OH⁻. For propylamine, substitute R with C₃H₇: C₃H₇NH₂ + H₂O ⇌ C₃H₇NH₃⁺ + OH⁻.

Step 3: Balance the reaction of propylamine with water. Ensure that the number of atoms on both sides of the equation is equal. In this case, the equation is already balanced as written: C₃H₇NH₂ + H₂O ⇌ C₃H₇NH₃⁺ + OH⁻.

Step 4: Write the neutralization reaction of propylamine with HBr. The general reaction for an amine (RNH₂) with a strong acid (HX) is: RNH₂ + HX → RNH₃⁺X⁻. For propylamine, substitute R with C₃H₇ and X with Br: C₃H₇NH₂ + HBr → C₃H₇NH₃⁺Br⁻.

Step 5: Balance the neutralization reaction. Ensure that the number of atoms and charges are balanced. In this case, the equation is already balanced as written: C₃H₇NH₂ + HBr → C₃H₇NH₃⁺Br⁻.

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