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To what final volume would 100 mL of 5.0 M KCl have to be diluted in order to make a solution that is 0.54 M KCl?
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13. Solutions
Dilutions
2:12 minutiProblema 57
Domanda del libro di testo
Determine the final volume, in milliliters, of each of the following: b. a 2.0% (m/v) LiCl solution prepared from 50.0 mL of a 10.0% (m/v) LiCl solution
Guida verificata passo dopo passo1
Identify the initial concentration and volume of the LiCl solution: 10.0% (m/v) and 50.0 mL.
Recognize that the final concentration of the LiCl solution needs to be 2.0% (m/v).
Use the dilution equation: C1V1 = C2V2, where C1 and V1 are the initial concentration and volume, and C2 and V2 are the final concentration and volume.
Substitute the known values into the equation: (10.0%)(50.0 mL) = (2.0%)(V2).
Solve for V2 to find the final volume of the solution.
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Mass/Volume Percent Concentration
Mass/volume percent (m/v) concentration is a way to express the concentration of a solution. It is calculated as the mass of solute (in grams) per 100 mL of solution. For example, a 2.0% (m/v) solution means there are 2 grams of solute in every 100 mL of solution. Understanding this concept is crucial for determining how to dilute or prepare solutions.
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Mass Percent Concept
Dilution Principle
The dilution principle states that when a solution is diluted, the amount of solute remains constant, while the volume of the solution increases. This can be expressed mathematically as C1V1 = C2V2, where C is concentration and V is volume. This principle is essential for calculating the final concentration and volume of a solution after dilution.
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00:58Dilutions
Volume Conversion
Volume conversion is the process of changing a volume measurement from one unit to another, such as from milliliters to liters. In this context, it is important to ensure that all volumes are expressed in the same units when performing calculations. Understanding how to convert between units is vital for accurately determining the final volume of a solution.
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02:10Conversion Factors (Simplified) Concept 2
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