Unisciti a migliaia di studenti che si affidano a noi per superare al meglio i loro esami!
Scelta multipla
Given a molecule with three chiral centers and no internal plane of symmetry, what is the maximum number of stereoisomers possible for this molecule ( where is the number of chiral centers)?
A
B
C
D
0 Commenti
Guida verificata passo dopo passo
1
Identify the number of chiral centers in the molecule, which is given as \(n = 3\).
Recall the formula for the maximum number of stereoisomers possible for a molecule with \(n\) chiral centers: \$2^{n}$.
Substitute the value of \(n\) into the formula: \$2^{3}$.
Calculate the expression \$2^{3}$, which represents the total number of stereoisomers without any internal symmetry considerations.
Since the molecule has no internal plane of symmetry, all stereoisomers are unique, so the maximum number of stereoisomers is \(8\).