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Scelta multipla
Predict the splitting pattern (multiplicity) for the following molecule:
A
A=singlet; B=singlet; C=doublet
B
A=singlet; B=quartet; C=triplet
C
A=singlet; B=doublet; C=triplet
D
A=singlet; B=doublet; C=quartet
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1
Identify the hydrogen environments in the molecule. In the given structure, there are three distinct hydrogen environments labeled as A, B, and C.
Determine the number of neighboring hydrogens for each environment using the n+1 rule, where n is the number of neighboring hydrogens.
For environment A, the methyl group (CH3) is adjacent to a carbonyl group (C=O) and has no neighboring hydrogens, resulting in a singlet (n=0, n+1=1).
For environment B, the methylene group (CH2) is adjacent to the methyl group (CH3) at C, which has 3 hydrogens. This results in a quartet (n=3, n+1=4).
For environment C, the methyl group (CH3) is adjacent to the methylene group (CH2) at B, which has 2 hydrogens. This results in a triplet (n=2, n+1=3).