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Draw the molecular orbital picture of octa-1,3,5,7-tetraene, indicating which is the HOMO and which is the LUMO.
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16. Conjugated Systems
Frontier Molecular Orbital Theory - Finding HOMO/LUMO
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Consider the Molecular Orbitals (MO’s) of the allyl anion. Which are the HOMO and LUMO?
A
HOMO = B, LUMO = C
B
HOMO = B, LUMO = A
C
HOMO = C, LUMO = A
D
HOMO = A, LUMO = C
E
HOMO = C, LUMO = B
Guida verificata passo dopo passo1
Identify the molecular orbitals (MOs) of the allyl anion. The allyl anion has three p orbitals that combine to form three molecular orbitals: one bonding, one non-bonding, and one antibonding.
Examine the images provided. Image A shows a molecular orbital with alternating phases, indicating a non-bonding orbital. Image B shows a bonding orbital with consistent phases across the molecule. Image C shows an antibonding orbital with nodes between each atom.
Understand the concept of HOMO (Highest Occupied Molecular Orbital) and LUMO (Lowest Unoccupied Molecular Orbital). The HOMO is the highest energy orbital that contains electrons, while the LUMO is the lowest energy orbital that does not contain electrons.
Determine the HOMO and LUMO based on the energy levels of the orbitals. The bonding orbital (Image B) is typically lower in energy and occupied, making it a candidate for HOMO. The antibonding orbital (Image C) is higher in energy and unoccupied, making it a candidate for LUMO.
Match the correct HOMO and LUMO to the options provided. Based on the analysis, HOMO = B and LUMO = C is the correct identification of the orbitals.
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