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Ch. 8 - Delocalized Electrons: Their Effect on Stability, pKa, and the Products of a Reaction • Aromaticity and Electronic Effects: An Introduction to the Reactions of Benzene
Bruice - Organic Chemistry 8th Edition
Bruice8th EditionOrganic ChemistryISBN: 9780135213711Non è quello che usi tu?Cambia libro di testo
Capitolo 8, Problema 65

Draw all the products of the following reaction:

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Step 1: Analyze the reactants. The molecule shown is a cyclooctatrienyl cation (C8H7+), which is aromatic due to its Huckel rule compliance (4n+2 π electrons, where n=1). It is bonded to a chlorine atom. The other reactant is hydroxide ion (HO⁻), a strong nucleophile and base.
Step 2: Consider the reaction mechanism. The hydroxide ion can act as a nucleophile and attack the positively charged carbon atom bonded to chlorine, leading to a substitution reaction. This is likely an SN2 mechanism due to the steric accessibility of the carbon.
Step 3: Predict the product of the substitution. The chlorine atom will be replaced by the hydroxide group, resulting in the formation of a cyclooctatrienyl alcohol (C8H7OH).
Step 4: Consider any possible side reactions. Since hydroxide is a strong base, it could also abstract a proton from the cyclooctatrienyl cation, leading to the formation of a neutral cyclooctatriene molecule (C8H8).
Step 5: Draw all possible products. The main product is cyclooctatrienyl alcohol (C8H7OH), and a potential side product is cyclooctatriene (C8H8). Ensure to represent the aromaticity in the structures of the products.

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