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Ch. 9 - Substitution and Elimination Reactions of Alkyl Halides
Bruice - Organic Chemistry 8th Edition
Bruice8th EditionOrganic ChemistryISBN: 9780135213711Non è quello che usi tu?Cambia libro di testo
Capitolo 9, Problema 23c,d

What is the major elimination product obtained from an E2 reaction of each of the following alkyl halides with hydroxide ion?
c.
d.

Guida verificata passo dopo passo
1
Step 1: Analyze the structure of the alkyl halide provided in each case. For the first structure (c), the molecule is 3-chloro-4-pentene, and for the second structure (d), the molecule is 2-fluoropentane. Identify the halogen atom and its position on the carbon chain.
Step 2: Recall the mechanism of the E2 elimination reaction. In an E2 reaction, a strong base (hydroxide ion in this case) abstracts a proton from a β-carbon (a carbon adjacent to the carbon bonded to the halogen), while the halogen leaves as a leaving group. This results in the formation of a double bond.
Step 3: For structure (c), identify the β-hydrogens available for elimination. The β-carbons are the carbons adjacent to the carbon bonded to chlorine. Consider the regioselectivity of the elimination reaction (Zaitsev's rule), which states that the more substituted alkene is generally the major product.
Step 4: For structure (d), identify the β-hydrogens available for elimination. The β-carbons are the carbons adjacent to the carbon bonded to fluorine. Apply Zaitsev's rule to determine the major product, keeping in mind that fluorine is a poor leaving group, which may influence the reaction.
Step 5: Draw the possible elimination products for each structure and determine the major product based on the stability of the alkenes formed. For structure (c), the double bond will likely form between the β-carbon and the α-carbon (carbon bonded to chlorine). For structure (d), the double bond will likely form between the β-carbon and the α-carbon (carbon bonded to fluorine).

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E2 Reaction Mechanism

The E2 (bimolecular elimination) reaction is a concerted mechanism where a base abstracts a proton from a β-carbon while a leaving group departs from the α-carbon, resulting in the formation of a double bond. This reaction typically requires strong bases and is characterized by a single transition state, leading to the formation of alkenes.
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Drawing the E2 Mechanism.

Zaitsev's Rule

Zaitsev's Rule states that in elimination reactions, the more substituted alkene is generally the major product. This occurs because more substituted alkenes are more stable due to hyperconjugation and the inductive effect, making them thermodynamically favored over less substituted counterparts.
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01:18
Defining Zaitsev’s Rule

Sterics and Regioselectivity

Sterics refers to the spatial arrangement of atoms in a molecule, which can influence the outcome of reactions. In E2 reactions, steric hindrance can affect which β-hydrogen is abstracted, leading to regioselectivity in the formation of the alkene product. Bulky bases may favor less hindered pathways, impacting the major product formed.
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02:53
Understanding steric effects.