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Give the important resonance forms for the possible enolate ions of the following:
(d)
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Ch. 22 - Condensations and Alpha Substitutions of Carbonyl Compounds
Wade9th EditionOrganic ChemistryISBN: 9780135213728
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TOC.tableOfContents
- Ch.1 - Structure and Bonding107
- Ch. 2 - Acids and Bases; Functional Groups115
- Ch.3 - Structure and Stereochemistry of Alkanes100
- Ch.4 - The Study of Chemical Reactions99
- Ch.5 - Stereochemistry93
- Ch.6 - Alkyl Halides; Nucleophilic Substitution118
- Ch. 7 - Structure and Synthesis of Alkenes; Elimination158
- Ch.8 - Reactions of Alkenes171
- Ch.9 - Alkynes91
- Ch.10 - Structure and Synthesis of Alcohols143
- Ch.11 - Reactions of Alcohols104
- Ch. 12 - Infrared Spectroscopy and Mass Spectrometry22
- Ch. 13 - Nuclear Magnetic Resonance Spectroscopy45
- Ch. 14 - Ethers, Epoxides, and Thioethers72
- Ch. 15 - Conjugated Systems, Orbital Symmetry, and Ultraviolet Spectroscopy89
- Ch. 16 - Aromatic Compounds74
- Ch. 17 - Reactions of Aromatic Compounds126
- Ch. 18 - Ketones and Aldehydes193
- Ch. 19 - Amines129
- Ch. 20 - Carboxylic Acids77
- Ch. 21 - Carboxylic Acid Derivatives141
- Ch. 22 - Condensations and Alpha Substitutions of Carbonyl Compounds175
- Ch. 23 - Carbohydrates and Nucleic Acids93
- Ch. 24 - Amino Acids, Peptides, and Proteins54
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Wade 9th EditionCh. 22 - Condensations and Alpha Substitutions of Carbonyl CompoundsProblema 5
Wade 9th EditionCh. 22 - Condensations and Alpha Substitutions of Carbonyl CompoundsProblema 5Capitolo 22, Problema 5
Predict the major products of the following reactions.
Guida verificata passo dopo passo1
Step 1: Analyze the reaction conditions. LDA (Lithium Diisopropylamide) is a strong, non-nucleophilic base used to deprotonate the most acidic hydrogen in the molecule, typically forming an enolate intermediate. CH3I or CH3CH2I are alkylating agents that react with the enolate to form a new C-C bond.
Step 2: For reaction (a), identify the most acidic hydrogen in the molecule. The ketone group has alpha hydrogens (hydrogens attached to the carbon adjacent to the carbonyl group). LDA will deprotonate one of these alpha hydrogens to form an enolate ion.
Step 3: The enolate formed in reaction (a) will then react with CH3I via an SN2 mechanism. The methyl group from CH3I will attach to the alpha carbon of the enolate, forming a new C-C bond.
Step 4: For reaction (b), the same process occurs. LDA deprotonates an alpha hydrogen of the cyclohexanone to form an enolate. The enolate reacts with CH3I, resulting in the methylation of the alpha carbon.
Step 5: For reaction (c), LDA deprotonates the alpha hydrogen adjacent to the carbonyl group in the bicyclic compound. The enolate formed reacts with CH3CH2I, leading to ethylation at the alpha carbon. Consider steric effects and regioselectivity in the product formation.
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Enolate Formation
Enolates are formed from carbonyl compounds (like ketones and aldehydes) through deprotonation at the alpha carbon. This reaction is typically facilitated by strong bases such as LDA (Lithium diisopropylamide). The resulting enolate ion is a nucleophile that can react with electrophiles, making it crucial for predicting reaction products in alkylation and acylation processes.
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02:26
Formation of Enolates
Alkylation of Enolates
Alkylation involves the reaction of an enolate ion with an alkyl halide, leading to the formation of a new carbon-carbon bond. The choice of alkyl halide affects the regioselectivity and stereochemistry of the product. In the context of the reactions shown, understanding how enolates react with methyl iodide (CH3I) is essential for predicting the major products.
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03:05Alkylation of Esters
Acylation of Enolates
Acylation is the process where an enolate reacts with an acyl chloride or an anhydride, resulting in the formation of a beta-keto ester or a beta-diketone. This reaction is significant in synthetic organic chemistry for constructing complex molecules. Recognizing the role of the enolate as a nucleophile in acylation helps in predicting the products of the reactions depicted in the question.
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03:05Alkylation of Esters
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