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Ch. 22 - Condensations and Alpha Substitutions of Carbonyl Compounds
Wade - Organic Chemistry 9th Edition
Wade9th EditionOrganic ChemistryISBN: 9780135213728Non è quello che usi tu?Cambia libro di testo
Capitolo 22, Problema 77e

Propose mechanisms for the following reactions.
(e)

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Step 1: Recognize the reaction type. This is an alpha-halogenation reaction of a ketone. The methyl group adjacent to the carbonyl group is the alpha position, which is susceptible to halogenation in the presence of bromine (Br₂) and acetic acid (AcOH).
Step 2: Protonation of the carbonyl oxygen. Acetic acid acts as a catalyst and protonates the oxygen atom of the carbonyl group, increasing the electrophilicity of the carbonyl carbon and making the alpha-hydrogens more acidic.
Step 3: Formation of the enol intermediate. The acidic environment facilitates the removal of an alpha-hydrogen by acetic acid, leading to the formation of the enol tautomer. The enol has a double bond between the alpha-carbon and the carbonyl carbon, and the hydroxyl group is attached to the carbonyl carbon.
Step 4: Electrophilic attack by bromine. The enol intermediate reacts with bromine (Br₂), where the double bond of the enol attacks a bromine molecule, leading to the formation of a bromonium ion. This results in the substitution of a bromine atom at the alpha-carbon.
Step 5: Regeneration of the ketone. The brominated enol tautomer undergoes tautomerization back to the ketone form, resulting in the final product, where the alpha-carbon is substituted with a bromine atom.

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