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In a DC circuit, a resistor has resistance and the current through it is . According to Ohm's law, what is the voltage drop across the resistor?
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Recall Ohm's law, which relates the voltage (V), current (I), and resistance (R) in a resistor. The law states that the voltage drop across a resistor is proportional to the current flowing through it and the resistance of the resistor.
Write down the mathematical expression of Ohm's law: \(V = I \times R\), where \(V\) is the voltage drop, \(I\) is the current, and \(R\) is the resistance.
Understand that the voltage drop is not given by division or addition of current and resistance, so expressions like \(V = \frac{I}{R}\), \(V = \frac{R}{I}\), or \(V = I + R\) are incorrect.
To find the voltage drop across the resistor, multiply the current \(I\) by the resistance \(R\) using the formula \(V = I \times R\).
This formula allows you to calculate the voltage drop if you know the current flowing through the resistor and its resistance.