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The position function for a particle moving on the -axis is . What is the particle's initial velocity?
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Identify the given position function of the particle: \(x(t) = -2t^2 + 18t + 7\).
Recall that velocity is the time derivative of position, so write the velocity function as \(v(t) = \frac{dx}{dt}\).
Differentiate the position function term-by-term: the derivative of \(-2t^2\) is \(-4t\), the derivative of \$18t$ is \(18\), and the derivative of the constant \(7\) is \(0\).
Combine these results to express the velocity function: \(v(t) = -4t + 18\).
To find the initial velocity, evaluate the velocity function at \(t=0\): \(v_0 = v(0) = -4(0) + 18\).