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Electric Potential and Capacitors - Physics

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  • What is electric potential?

    Electric potential is the potential for creating electric potential energy if a charge is placed at a given point. It is measured in volts (V), which are joules per coulomb (J/C).

  • How is electric potential energy related to electric potential?

    Electric potential energy is the interaction energy of a charged particle with source charges, while electric potential is the potential created by source charges. Potential energy depends on the charge, potential does not.

  • What is the unit of electric potential difference?

    The unit of electric potential difference is the volt (V), equivalent to joules per coulomb (J/C).

  • How does electric potential vary inside a parallel-plate capacitor?

    Electric potential increases linearly from the negative plate to the positive plate inside a parallel-plate capacitor.

  • What is the relationship between electric field and equipotential surfaces?

    The electric field is always perpendicular to equipotential surfaces.

  • How is the electric field strength related to potential difference and plate separation in a parallel-plate capacitor?

    Electric field strength \(E\) is given by \(E=\frac{V}{d}\), where \(V\) is the potential difference and \(d\) is the plate separation.

  • What is capacitance and its SI unit?

    Capacitance is the constant of proportionality between the charge on the capacitor plates and the potential difference between them. Its SI unit is the farad (F).

  • How does inserting a dielectric affect a capacitor?

    Inserting a dielectric decreases the electric field and potential difference but increases the capacitance by a factor called the dielectric constant \(\kappa\).

  • What is the formula for the energy stored in a charged capacitor?

    The energy stored is \(U=\frac{1}{2}CV^2\), where \(C\) is capacitance and \(V\) is the voltage.

  • What is an electron volt (eV)?

    An electron volt is the kinetic energy gained by an electron accelerating through a potential difference of 1 volt. It is a unit of energy equal to approximately \(1.6 \times 10^{-19}\) joules.

  • How is electric potential due to a point charge calculated?

    Electric potential at distance \(r\) from a point charge \(q\) is \(V=\frac{kq}{r}\), where \(k\) is Coulomb's constant.

  • What happens to a positive charge moving from high to low electric potential?

    Its electric potential energy decreases and kinetic energy increases; the charge speeds up.

  • What is the potential difference created by a battery?

    A battery creates a potential difference by chemical separation of charges, typically about 1.5 V for an alkaline battery.

  • What are the properties of a conductor in electrostatic equilibrium?

    Excess charge resides on the surface, the electric field inside is zero, the exterior field is perpendicular to the surface, and the entire conductor is at the same potential.

  • How is the electric potential of many charges calculated?

    The total electric potential at a point is the scalar sum of the potentials due to each individual charge.

  • What is the energy density of the electric field in a capacitor?

    Energy density is the energy stored per unit volume in the electric field, with units of joules per cubic meter (J/m³).

  • How does the capacitance of a parallel-plate capacitor depend on its geometry?

    Capacitance increases with larger plate area and decreases with greater plate separation.

  • What is the effect on charge and electric field when capacitor plates are pulled apart while disconnected from a battery?

    The charge remains constant and the electric field remains constant.

  • What is the effect on charge and electric field when capacitor plates are pulled apart while connected to a battery?

    The charge decreases and the electric field decreases.

  • How is the final speed of a charged particle moving through a potential difference found?

    Use conservation of energy: kinetic energy change equals charge times potential difference, \(\frac{1}{2}mv_f^2 - \frac{1}{2}mv_i^2 = q(V_i - V_f)\).