Domanda del libro di testo
What is the specific heat of a metal substance if 165 kJ of heat is needed to raise 4.1 kg of the metal from 18.0°C to 37.2°C?
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Ch. 19 - Heat and the First Law of Thermodynamics
Giancoli Douglas5th editionPhysics for Scientists and EngineersISBN: 9780137488179
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TOC.tableOfContents
- Ch. 01 - Introduction, Measurement, Estimating10
- Ch. 02 - Describing Motion: Kinematics in One Dimension30
- Ch. 03 - Kinematics in Two or Three Dimensions; Vectors15
- Ch. 04 - Dynamics: Newton's Laws of Motion16
- Ch. 05 - Using Newton's Laws: Friction, Circular Motion, Drag Forces22
- Ch. 06 - Gravitation and Newton's Synthesis10
- Ch. 07 - Work and Energy21
- Ch. 08 - Conservation of Energy33
- Ch. 09 - Linear Momentum26
- Ch. 10 - Rotational Motion41
- Ch. 11 - Angular Momentum; General Rotation27
- Ch. 12 - Static Equilibrium; Elasticity and Fracture27
- Ch. 13 - Fluids28
- Ch. 14 - Oscillations14
- Ch. 15 - Wave Motion35
- Ch. 16 - Sound5
- Ch. 17 - Temperature, Thermal Expansion, and the Ideal Gas Law40
- Ch. 18 - Kinetic Theory of Gases18
- Ch. 19 - Heat and the First Law of Thermodynamics31
- Ch. 20 - Second Law of Thermodynamics32
- Ch. 21 - Electric Charge and Electric Field7
- Ch. 23 - Electric Potential20
- Ch. 24 - Capacitance, Dielectrics, Electric Energy, Storage15
- Ch. 25 - Electric Current and Resistance32
- Ch. 26 - DC Circuits22
- Ch. 27 - Magnetism21
- Ch. 28 - Sources of Magnetic Field24
- Ch. 29 - Electromagnetic Induction and Faraday's Law21
- Ch. 30 - Inductance, Electromagnetic Oscillations, and AC Circuits42
- Ch. 31 - Maxwell's Equations and Electromagnetic Waves25
- Ch. 32 - Light: Reflection and Refraction42
- Ch. 33 - Lenses and Optical Instruments21
- Ch. 34 - The Wave Nature of Light: Interference and Polarization26
- Ch. 35 - Diffraction24
- Ch. 36 - The Special Theory of Relativity29
- Ch. 38 - Quantum Mechanics1
- Ch. 40 - Molecules and Solids6
- Ch. 43 - Elementary Particles3
- Ch. 44 - Astrophysics and Cosmology9
Giancoli Douglas5th editionPhysics for Scientists and EngineersISBN: 9780137488179Non è quello che usi tu?Cambia libro di testo
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Giancoli Douglas 5th editionCh. 19 - Heat and the First Law of ThermodynamicsProblema 3
Giancoli Douglas 5th editionCh. 19 - Heat and the First Law of ThermodynamicsProblema 3Capitolo 19, Problema 3
An average active person consumes about 2500 Cal a day.
(a) What is this in joules?
(b) What is this in kilowatt-hours?
(c) If your power company charges about per kilowatt-hour, how much would your energy cost per day if you bought it from the power company? Could you feed yourself on this much money per day?
Guida verificata passo dopo passo1
Step 1: Convert the energy from calories to joules. Use the conversion factor: 1 Cal (food calorie) = 4184 J. Multiply 2500 Cal by 4184 J/Cal to find the energy in joules.
Step 2: Convert the energy from joules to kilowatt-hours. Use the conversion factor: 1 kilowatt-hour (kWh) = 3.6 × 10^6 J. Divide the energy in joules by 3.6 × 10^6 J/kWh to find the energy in kilowatt-hours.
Step 3: Calculate the cost of this energy if purchased from a power company. Multiply the energy in kilowatt-hours by the cost per kilowatt-hour (assume the cost is given, e.g., \$0.12 per kWh).
Step 4: Compare the calculated energy cost to the cost of feeding yourself. Consider whether the energy cost is higher or lower than the daily cost of food.
Step 5: Reflect on the efficiency of biological energy consumption versus electrical energy consumption, noting that the human body is highly efficient at converting food energy into usable energy for daily activities.
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Concetti chiave
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Calorie to Joule Conversion
A calorie (Cal) is a unit of energy defined as the amount of heat needed to raise the temperature of one gram of water by one degree Celsius. In physics, energy is often measured in joules (J), where 1 Cal is equivalent to approximately 4.184 joules. Understanding this conversion is essential for translating dietary energy consumption into a more universally recognized energy unit.
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Percorso guidato
07:46
Unit Conversions
Kilowatt-Hour (kWh)
A kilowatt-hour is a unit of energy equivalent to one kilowatt (1000 watts) of power used for one hour. It is commonly used by electric companies to measure energy consumption. To convert joules to kilowatt-hours, one can use the conversion factor where 1 kWh equals 3.6 million joules. This concept is crucial for understanding energy costs in terms of household electricity usage.
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Cost of Energy
The cost of energy refers to the price paid for electricity, typically measured in cents per kilowatt-hour. To determine daily energy costs based on personal energy consumption, one can multiply the daily kWh usage by the cost per kWh. This concept helps in evaluating the economic feasibility of energy consumption from a power company compared to dietary energy intake.
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Percorso guidato
04:10Intro to Energy & Types of Energy
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Domanda del libro di testo
The heat capacity, C, of an object is defined as the amount of heat needed to raise its temperature by 1 °C. Thus, to raise the temperature by ∆T requires heat Q given by Q = C∆T. What is the heat capacity of 38 kg of water?
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Domanda del libro di testo
(a) How long does it take a 750-W coffeepot to bring to a boil 0.75 L of water at sea level initially at 11°C? Assume that the part of the pot which is heated with the water is made of 250 g of aluminum, and that no water boils away.
(b) For how long could this amount of energy run a 60-W lightbulb?
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