Skip to main content
Ch. 20 - Second Law of Thermodynamics
Giancoli Douglas - Physics for Scientists and Engineers 5th edition
Giancoli Douglas5th editionPhysics for Scientists and EngineersISBN: 9780137488179Non è quello che usi tu?Cambia libro di testo
Tutti i libri di testoGiancoli Douglas 5th editionCh. 20 - Second Law of ThermodynamicsProblema 20a
Capitolo 20, Problema 20a

One mole of monatomic gas undergoes a Carnot cycle with TH = 350°C and TL = 210°C. The initial pressure is 8.8 atm. During the isothermal expansion, the volume doubles. Find the values of the pressure and volume at the points a, b, c, and d of Fig. 20–5.

Guida verificata passo dopo passo
1
Step 1: Convert the given temperatures from Celsius to Kelvin. Use the formula T(K) = T(°C) + 273.15. For T_H = 350°C, calculate T_H in Kelvin. Similarly, for T_L = 210°C, calculate T_L in Kelvin.
Step 2: Identify the key points in the Carnot cycle (a, b, c, d) and their corresponding processes: (a to b) isothermal expansion at T_H, (b to c) adiabatic expansion, (c to d) isothermal compression at T_L, and (d to a) adiabatic compression. Use the given information that the volume doubles during the isothermal expansion (a to b).
Step 3: For the isothermal expansion (a to b), use the ideal gas law, PV = nRT, to calculate the pressure at point b. Since the volume doubles, V_b = 2V_a. The temperature remains constant at T_H, so P_a * V_a = P_b * V_b. Solve for P_b.
Step 4: For the adiabatic expansion (b to c), use the adiabatic condition for a monatomic gas: P * V^(γ) = constant, where γ = 5/3 for a monatomic gas. Use the known values of P_b, V_b, and the relationship to find P_c and V_c. Note that the temperature at point c is T_L.
Step 5: For the isothermal compression (c to d) and adiabatic compression (d to a), repeat similar calculations. For the isothermal compression, use P_c * V_c = P_d * V_d, where the temperature is T_L. For the adiabatic compression, use the adiabatic condition again to find P_a and V_a, ensuring the cycle closes back to the initial state.

Risposta video verificata per un problema simile:

Questa soluzione video è stata consigliata dai nostri tutor come utile per risolvere questo problema.
Durata del video:
13m

Concetti chiave

Ecco i concetti essenziali che devi comprendere per rispondere correttamente alla domanda.

Carnot Cycle

The Carnot cycle is a theoretical thermodynamic cycle that provides the maximum possible efficiency for a heat engine operating between two temperature reservoirs. It consists of four reversible processes: two isothermal (constant temperature) and two adiabatic (no heat exchange). Understanding this cycle is crucial for analyzing the performance of real engines and calculating work done and heat transfer during the cycle.
Video consigliato:
Percorso guidato
06:28
The Carnot Cycle and Maximum Theoretical Efficiency

Ideal Gas Law

The Ideal Gas Law relates the pressure, volume, temperature, and number of moles of an ideal gas through the equation PV = nRT. In this context, it is essential for determining the state variables of the gas at different points in the Carnot cycle, especially during isothermal and adiabatic processes. This law allows us to calculate changes in pressure and volume as the gas undergoes transformations.
Video consigliato:
Percorso guidato
07:21
Ideal Gases and the Ideal Gas Law

Isothermal Process

An isothermal process occurs at a constant temperature, meaning that any heat added to the system is used to do work rather than change the internal energy. For an ideal gas, this implies that the product of pressure and volume remains constant (PV = constant). In the context of the Carnot cycle, understanding isothermal expansion and compression is vital for calculating the work done and the changes in pressure and volume at specific points in the cycle.
Video consigliato:
Percorso guidato
06:13
Entropy & Ideal Gas Processes
Pratica correlata
Domanda del libro di testo

(II) What is the temperature inside an ideal refrigerator–freezer that operates with a COP = 7.0 in a 22°C room?

1820
views
Domanda del libro di testo

One mole of monatomic gas undergoes a Carnot cycle with TH = 350°C and TL = 210°C. The initial pressure is 8.8 atm. During the isothermal expansion, the volume doubles. Calculate the efficiency of the cycle using Eqs. 20–1 and 20–3.

1239
views
Domanda del libro di testo

(II) 1.00 mole of nitrogen (N₂) gas and 1.00 mole of argon (Ar) gas are in separate, equal-sized, insulated containers at the same temperature. The containers are then connected and the gases (assumed ideal) allowed to mix. What is the change in entropy

(a) of the system

1409
views
Domanda del libro di testo

What is the coefficient of performance of an ideal heat pump that extracts heat from 6°C air outside and deposits heat inside a house at 24°C?

1505
views
Domanda del libro di testo

The working substance of a certain Carnot engine is 1.0 mol of an ideal monatomic gas. During the isothermal expansion portion of this engine’s cycle, the volume of the gas doubles, while during the adiabatic expansion the volume increases by a factor of 6.2. The work output of the engine is 920 J in each cycle. Compute the temperatures of the two reservoirs between which this engine operates.

1886
views
Domanda del libro di testo

A particular car does work at the rate of about 7.0 kJ/s when traveling at a steady 21.8 m/s along a level road. This is the work done against friction. The car can travel 17 km on 1.0 L of gasoline at this speed (about 40 mi/gal). What is the minimum value for TH if TL is 25°C? The energy available from 1.0 L of gas is 3.2 x 10⁷ J.

1241
views