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Ch 13: Gravitation
Young & Freedman Calc - University Physics 14th Edition
Young & Freedman Calc14th EditionUniversity PhysicsISBN: 9780321973610Non è quello che usi tu?Cambia libro di testo
Capitolo 13, Problema 33a

A uniform, solid, 1000.0-kg sphere has a radius of 5.00 m. Find the gravitational force this sphere exerts on a 2.00-kg point mass placed at the following distances from the center of the sphere: (i) 5.01 m, (ii) 2.50 m.

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Step 1: Understand the problem. We need to calculate the gravitational force exerted by a sphere on a point mass at two different distances. The gravitational force can be calculated using Newton's law of universal gravitation.
Step 2: Recall the formula for gravitational force: F = (GmM)r2, where G is the gravitational constant, m is the mass of the point mass, M is the mass of the sphere, and r is the distance from the center of the sphere to the point mass.
Step 3: For part (i), where the distance is 5.01 m, use the formula directly since the point mass is outside the sphere. Substitute G = 6.674 imes 10^{-11} \(\text{ N m}\)^2/\(\text{kg}\)^2, m = 2.00 \(\text{ kg}\), M = 1000.0 \(\text{ kg}\), and r = 5.01 \(\text{ m}\) into the formula.
Step 4: For part (ii), where the distance is 2.50 m, the point mass is inside the sphere. According to the shell theorem, only the mass within the radius of 2.50 m contributes to the gravitational force. Calculate the mass of the sphere within this radius using the volume ratio: M' = M imes rac{(2.50)^3}{(5.00)^3}.
Step 5: Use the gravitational force formula again for part (ii) with the new mass M' and distance r = 2.50 \(\text{ m}\). Substitute the values into the formula to find the gravitational force.

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