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Ch 13: Gravitation
Young & Freedman Calc - University Physics 14th Edition
Young & Freedman Calc14th EditionUniversity PhysicsISBN: 9780321973610Non è quello che usi tu?Cambia libro di testo
Capitolo 13, Problema 12a

The mass of Venus is 81.5% that of the earth, and its radius is 94.9% that of the earth. Compute the acceleration due to gravity on the surface of Venus from these data.

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Start by recalling the formula for gravitational acceleration on the surface of a planet: \( g = \frac{G \cdot M}{R^2} \), where \( G \) is the gravitational constant, \( M \) is the mass of the planet, and \( R \) is the radius of the planet.
Express the mass of Venus \( M_v \) in terms of Earth's mass \( M_e \): \( M_v = 0.815 \cdot M_e \).
Express the radius of Venus \( R_v \) in terms of Earth's radius \( R_e \): \( R_v = 0.949 \cdot R_e \).
Substitute \( M_v \) and \( R_v \) into the gravitational acceleration formula for Venus: \( g_v = \frac{G \cdot (0.815 \cdot M_e)}{(0.949 \cdot R_e)^2} \).
Simplify the expression to find \( g_v \) in terms of Earth's gravitational acceleration \( g_e \), where \( g_e = \frac{G \cdot M_e}{R_e^2} \). This gives \( g_v = g_e \cdot \frac{0.815}{0.949^2} \).

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Gravitational Acceleration

Gravitational acceleration is the acceleration of an object due to the force of gravity acting on it. It is calculated using the formula g = G * M / R^2, where G is the gravitational constant, M is the mass of the celestial body, and R is its radius. This formula helps determine how strong the gravitational pull is on the surface of a planet like Venus.
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Understanding the proportions of mass and radius between two celestial bodies is crucial for comparing their gravitational forces. In this context, Venus's mass is 81.5% of Earth's, and its radius is 94.9% of Earth's. These proportions allow us to adjust the gravitational formula to calculate Venus's surface gravity relative to Earth's known values.
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