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Ch 24: Capacitance and Dielectrics
Young & Freedman Calc - University Physics 14th Edition
Young & Freedman Calc14th EditionUniversity PhysicsISBN: 9780321973610Non è quello che usi tu?Cambia libro di testo
Capitolo 24, Problema 14c

Figure E24.1424.14 shows a system of four capacitors, where the potential difference across ab is 50.050.0 V. How much charge is stored in each of the 10.010.0-μ\(\mu\)F and the 9.09.0-μ\(\mu\)F capacitors?
Diagram of four capacitors: 10.0 µF, 5.0 µF, 8.0 µF, 9.0 µF, connected between points a and b, with 50.0 V across ab.

Guida verificata passo dopo passo
1
Identify the configuration of the capacitors in the circuit. The 10.0 μF and 9.0 μF capacitors are in series with the 5.0 μF and 8.0 μF capacitors, which are in parallel.
Calculate the equivalent capacitance of the parallel capacitors (5.0 μF and 8.0 μF). Use the formula for capacitors in parallel: C_parallel = C2 + C3, where C2 = 5.0 μF and C3 = 8.0 μF.
Determine the equivalent capacitance of the series capacitors (10.0 μF and 9.0 μF) with the equivalent parallel capacitance. Use the formula for capacitors in series: 1/C_series = 1/C1 + 1/C_parallel + 1/C4, where C1 = 10.0 μF and C4 = 9.0 μF.
Calculate the charge stored in the 10.0 μF capacitor using the formula Q = C * V, where C is the capacitance and V is the potential difference across the capacitor. The potential difference across the series capacitors is the same as the total potential difference (50.0 V).
Calculate the charge stored in the 9.0 μF capacitor using the same formula Q = C * V, considering the potential difference across the series capacitors.

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Capacitance

Capacitance is the ability of a capacitor to store charge per unit voltage, defined as C = Q/V, where C is capacitance in farads, Q is charge in coulombs, and V is voltage in volts. In this problem, the capacitors have values in microfarads (µF), which is a common unit for small capacitances. Understanding capacitance is essential for calculating the charge stored in each capacitor when a potential difference is applied.
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Capacitors & Capacitance (Intro)

Series and Parallel Capacitors

Capacitors can be connected in series or parallel, affecting the total capacitance of the circuit. In series, the total capacitance (C_total) is given by 1/C_total = 1/C1 + 1/C2 + ... for each capacitor. In parallel, the total capacitance is the sum of individual capacitances: C_total = C1 + C2 + ... Understanding how to combine capacitors in these configurations is crucial for solving the problem regarding the charge distribution across the capacitors.
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Combining Capacitors in Series & Parallel

Charge Distribution

When capacitors are connected in a circuit with a voltage applied, the charge stored on each capacitor depends on its capacitance and the voltage across it. For capacitors in parallel, they share the same voltage, while in series, the charge is the same across each capacitor. This concept is vital for determining how much charge is stored in the 10.0 µF and 9.0 µF capacitors when a 50.0 V potential difference is applied across the entire system.
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Probability Distribution Graph
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