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Ch 34: Geometric Optics
Young & Freedman Calc - University Physics 14th Edition
Young & Freedman Calc14th EditionUniversity PhysicsISBN: 9780321973610Non è quello che usi tu?Cambia libro di testo
Capitolo 34, Problema 51a

Where is the near point of an eye for which a contact lens with a power of +2.75 diopters is prescribed?

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Understand the problem: The power of a lens (in diopters) is related to its focal length (in meters) by the formula: P=1f. Here, the power of the contact lens is given as +2.75 diopters, and we need to find the focal length of the lens, which corresponds to the near point of the eye.
Rearrange the formula to solve for the focal length: f=1P. Substitute the given power of the lens, P=2.75, into the equation.
Perform the calculation to find the focal length: f=12.75. This will give the focal length in meters.
Interpret the result: The focal length of the lens represents the distance at which the lens focuses light. Since the lens is correcting for the near point of the eye, this focal length corresponds to the near point distance of the eye with the contact lens in place.
Convert the focal length to centimeters if needed (1 meter = 100 centimeters) for a more practical representation of the near point distance.

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Power of a Lens

The power of a lens, measured in diopters, is the reciprocal of its focal length in meters. A positive power indicates a converging lens, which is used to correct hyperopia (farsightedness). In this case, a contact lens with a power of +2.75 diopters means it has a focal length of approximately 0.364 meters, or 36.4 centimeters.
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Near Point

The near point of the eye is the closest distance at which an object can be seen clearly without strain. For a normal eye, this distance is typically around 25 centimeters. However, for individuals with vision impairments, such as hyperopia, the near point can be farther away, necessitating corrective lenses to bring it closer.
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Lens Formula

The lens formula relates the object distance (u), image distance (v), and focal length (f) of a lens, expressed as 1/f = 1/v - 1/u. This formula is essential for determining how a lens affects the position of the image formed by an object. In the context of contact lenses, it helps calculate the effective near point when a lens is used.
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