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Ch 39: Particles Behaving as Waves
Young & Freedman Calc - University Physics 14th Edition
Young & Freedman Calc14th EditionUniversity PhysicsISBN: 9780321973610Non è quello che usi tu?Cambia libro di testo
Capitolo 39, Problema 19

A hydrogen atom is in a state with energy −1.51-1.51 eV. In the Bohr model, what is the angular momentum of the electron in the atom, with respect to an axis at the nucleus?

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1
Identify the energy level of the hydrogen atom using the given energy. In the Bohr model, the energy of an electron in the nth orbit is given by the formula: E=-E1n2, where E1 is the ground state energy (-13.6 eV) and n is the principal quantum number.
Rearrange the formula to solve for n: n=E1E. Substitute E=-1.51 eV and E1=-13.6 eV to calculate n.
Recall that in the Bohr model, the angular momentum of the electron is quantized and given by the formula: L=n⁢ħ, where ħ is the reduced Planck's constant (ħ=h2).
Substitute the value of n obtained from the previous step into the angular momentum formula. This will give the angular momentum of the electron in terms of ħ.
Express the final angular momentum in the form L=n⁢ħ, where n is the principal quantum number you calculated earlier.

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Bohr Model of the Atom

The Bohr model describes the hydrogen atom as having electrons in fixed orbits around the nucleus, with quantized energy levels. Each orbit corresponds to a specific energy state, and the electron can only occupy these discrete levels. The model introduces the idea that angular momentum is quantized, leading to specific values for the electron's motion.
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Quantization of Angular Momentum

In the Bohr model, the angular momentum of an electron in orbit is quantized and given by the formula L = nħ, where L is the angular momentum, n is a positive integer (the principal quantum number), and ħ is the reduced Planck's constant. This means that the electron can only have certain allowed values of angular momentum, which are integral multiples of ħ.
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06:18
Intro to Angular Momentum

Energy Levels in Hydrogen Atom

The energy levels of a hydrogen atom are determined by the formula E_n = -13.6 eV/n², where E_n is the energy of the nth level. For an energy of -1.51 eV, we can find the corresponding principal quantum number n. This value of n is essential for calculating the angular momentum, as it directly relates to the quantized states of the electron.
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A triply ionized beryllium ion, Be3+ (a beryllium atom with three electrons removed), behaves very much like a hydrogen atom except that the nuclear charge is four times as great. For the hydrogen atom, the wavelength of the photon emitted in the n=2n = 2 to n=1n = 1 transition is 122122 nm (see Example 39.639.6). What is the wavelength of the photon emitted when a Be3+ ion undergoes this transition?

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