Ch 05: Applying Newton's Laws

Young & Freedman Calc - University Physics 15th Edition

Young & Freedman Calc15th EditionUniversity PhysicsISBN: 9780135159552Non è quello che usi tu?Cambia libro di testo

Young & Freedman Calc 15th Edition

Ch 05: Applying Newton's Laws

Problema 54d

Capitolo 5, Problema 54d

The Cosmo Clock 21 Ferris wheel in Yokohama, Japan, has a diameter of $100$ m. Its name comes from its $60$ arms, each of which can function as a second hand (so that it makes one revolution every $60.0$ s). What then would be the passenger's apparent weight at the lowest point?

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Determine the centripetal acceleration of the passenger at the lowest point. The centripetal acceleration is given by the formula:

a c_{r} = v^{2} / r

, where

v

is the tangential speed and

r

is the radius of the Ferris wheel.

Calculate the tangential speed

v

of the passenger. The tangential speed is related to the period of rotation

T

and the radius

r

by the formula:

v = \frac{2 π r}{T}

. Use the diameter of the Ferris wheel to find the radius

r = \frac{100}{2} = 50 m

, and the period

T = 60 s

Determine the net force acting on the passenger at the lowest point. At this point, the forces acting on the passenger are the gravitational force

F g_{= m g}

(downward) and the normal force

F n

(upward). The net force is the centripetal force required to keep the passenger moving in a circular path:

F c = m a c_{r}

Relate the normal force to the net force. At the lowest point, the normal force is greater than the gravitational force because it must provide the centripetal force in addition to balancing the passenger's weight. The relationship is:

F n = F g + F c

, or equivalently:

F n = m g + m a c_{r}

Substitute the expressions for

a c_{r}

and

v

into the equation for

F n

. This gives:

F n = m g + m \frac{{\frac{2 π r}{T}}^{2}}{r}

. Simplify this expression to find the apparent weight of the passenger at the lowest point.

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Centripetal Acceleration

Centripetal acceleration is the acceleration directed towards the center of a circular path that an object follows. It is necessary for maintaining circular motion and is calculated using the formula a_c = v^2 / r, where v is the tangential speed and r is the radius of the circular path. In the context of the Ferris wheel, this acceleration affects the forces acting on the passengers as they move along the circular trajectory.

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Percorso guidato

06:48

Intro to Centripetal Forces

Apparent Weight

Apparent weight refers to the sensation of weight experienced by an object or person, which can differ from actual weight due to acceleration. It is influenced by the net forces acting on the object, including gravitational force and any additional forces due to motion, such as centripetal force. At the lowest point of the Ferris wheel, the apparent weight is the sum of the gravitational force and the centripetal force required to keep the passenger moving in a circle.

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Percorso guidato

10:19

Torque Due to Weight

Forces in Circular Motion

In circular motion, several forces interact to keep an object moving along a curved path. The key forces include gravitational force, which pulls objects downward, and the normal force, which acts perpendicular to the surface. At the lowest point of the Ferris wheel, the normal force is greater than the gravitational force, resulting in an increased apparent weight for the passengers due to the need for centripetal force to maintain circular motion.

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Percorso guidato

03:48

Intro to Circular Motion

Pratica correlata

Domanda del libro di testo

The Cosmo Clock 21 Ferris wheel in Yokohama, Japan, has a diameter of $100$ m. Its name comes from its $60$ arms, each of which can function as a second hand (so that it makes one revolution every $60.0$ s). Find the speed of the passengers when the Ferris wheel is rotating at this rate.

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views

Domanda del libro di testo

The Cosmo Clock 21 Ferris wheel in Yokohama, Japan, has a diameter of $100$ m. Its name comes from its $60$ arms, each of which can function as a second hand (so that it makes one revolution every $60.0$ s). What would be the time for one revolution if the passenger's apparent weight at the highest point were zero?

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views

Domanda del libro di testo

The Cosmo Clock 21 Ferris wheel in Yokohama, Japan, has a diameter of $100$ m. Its name comes from its $60$ arms, each of which can function as a second hand (so that it makes one revolution every $60.0$ s). A passenger weighs $882$ N at the weight-guessing booth on the ground. What is his apparent weight at the highest and at the lowest point on the Ferris wheel?

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views

The Cosmo Clock 21 Ferris wheel in Yokohama, Japan, has a diameter of 100100100 m. Its name comes from its 606060 arms, each of which can function as a second hand (so that it makes one revolution every 60.060.060.0 s). What then would be the passenger's apparent weight at the lowest point?

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Concetti chiave

Centripetal Acceleration

Apparent Weight

Forces in Circular Motion

The Cosmo Clock 21 Ferris wheel in Yokohama, Japan, has a diameter of $100$ m. Its name comes from its $60$ arms, each of which can function as a second hand (so that it makes one revolution every $60.0$ s). What then would be the passenger's apparent weight at the lowest point?