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Ch 19: The First Law of Thermodynamics
Young & Freedman Calc - University Physics 15th Edition
Young & Freedman Calc15th EditionUniversity PhysicsISBN: 9780135159552Non è quello che usi tu?Cambia libro di testo
Capitolo 19, Problema 6a

A gas undergoes two processes. In the first, the volume remains constant at 0.2000.200 m3 and the pressure increases from 2.00×1052.00\(\times\)10^5 Pa to 5.00×1055.00\(\times\)10^5 Pa. The second process is a compression to a volume of 0.1200.120 m3 at a constant pressure of 5.00×1055.00\(\times\)10^5 Pa. In a pVpV-diagram, show both processes.

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Start by understanding the pV-diagram, which is a graphical representation of the pressure (p) versus volume (V) for a given process. In this problem, we have two distinct processes to represent.
For the first process, the volume remains constant at 0.200 m^3 while the pressure increases from 2.00 * 10^5 Pa to 5.00 * 10^5 Pa. On a pV-diagram, this is represented as a vertical line because the volume does not change, only the pressure does.
For the second process, the gas is compressed to a volume of 0.120 m^3 at a constant pressure of 5.00 * 10^5 Pa. On a pV-diagram, this is represented as a horizontal line because the pressure remains constant while the volume decreases.
To plot these processes on the pV-diagram, start by marking the initial point of the first process at (0.200 m^3, 2.00 * 10^5 Pa). Draw a vertical line up to the point (0.200 m^3, 5.00 * 10^5 Pa) to represent the first process.
Next, from the endpoint of the first process, draw a horizontal line to the point (0.120 m^3, 5.00 * 10^5 Pa) to represent the second process. This completes the representation of both processes on the pV-diagram.

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Pressure-Volume (pV) Diagram

A pV diagram is a graphical representation of the changes in pressure and volume of a gas during thermodynamic processes. It helps visualize how these properties interact, with pressure on the y-axis and volume on the x-axis. In this question, the diagram will show a vertical line for the constant volume process and a horizontal line for the constant pressure process.
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Work and PV Diagrams

Isovolumetric Process

An isovolumetric process, also known as an isochoric process, occurs when the volume of a system remains constant. During this process, any change in pressure is due to changes in temperature or the amount of gas. In the given question, the first process is isovolumetric, where the pressure increases while the volume remains at 0.200 m^3.
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Heat Equations for Isobaric & Isovolumetric Processes

Isobaric Process

An isobaric process is a thermodynamic process in which the pressure remains constant while the volume changes. This type of process is represented by a horizontal line on a pV diagram. In the question, the second process is isobaric, where the gas is compressed to a volume of 0.120 m^3 while maintaining a constant pressure of 5.00 * 10^5 Pa.
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Heat Equations for Isobaric & Isovolumetric Processes
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A gas undergoes two processes. In the first, the volume remains constant at 0.2000.200 m3 and the pressure increases from 2.00×1052.00\(\times\)10^5 Pa to 5.00×1055.00\(\times\)10^5 Pa. The second process is a compression to a volume of 0.1200.120 m3 at a constant pressure of 5.00×1055.00\(\times\)10^5 Pa. Find the total work done by the gas during both processes.

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The graph in Fig. E19.419.4 shows a pVpV-diagram of the air in a human lung when a person is inhaling and then exhaling a deep breath. Such graphs, obtained in clinical practice, are normally somewhat curved, but we have modeled one as a set of straight lines of the same general shape. (Important: The pressure shown is the gauge pressure, not the absolute pressure.) How many joules of net work does this person's lung do during one complete breath?

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