Domanda del libro di testo
The circuit shown in Fig. E contains two batteries, each with an emf and an internal resistance, and two resistors. Find the current in the circuit (magnitude and direction).
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Ch 25: Current, Resistance, and EMF
Young & Freedman Calc15th EditionUniversity PhysicsISBN: 9780135159552
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TOC.tableOfContents
- Ch 01: Units, Physical Quantities & Vectors37
- Ch 02: Motion Along a Straight Line57
- Ch 03: Motion in Two or Three Dimensions45
- Ch 04: Newton's Laws of Motion23
- Ch 05: Applying Newton's Laws54
- Ch 06: Work & Kinetic Energy11
- Ch 07: Potential Energy & Conservation6
- Ch 08: Momentum, Impulse, and Collisions15
- Ch 09: Rotation of Rigid Bodies37
- Ch 10: Dynamics of Rotational Motion44
- Ch 11: Equilibrium & Elasticity27
- Ch 12: Fluid Mechanics27
- Ch 13: Gravitation34
- Ch 14: Periodic Motion26
- Ch 15: Mechanical Waves22
- Ch 16: Sound & Hearing28
- Ch 17: Temperature and Heat28
- Ch 18: Thermal Properties of Matter35
- Ch 19: The First Law of Thermodynamics29
- Ch 20: The Second Law of Thermodynamics18
- Ch 21: Electric Charge and Electric Field28
- Ch 22: Gauss' Law21
- Ch 23: Electric Potential31
- Ch 24: Capacitance and Dielectrics18
- Ch 25: Current, Resistance, and EMF24
- Ch 26: Direct-Current Circuits29
- Ch 27: Magnetic Field and Magnetic Forces16
- Ch 28: Sources of Magnetic Field10
- Ch 29: Electromagnetic Induction22
- Ch 30: Inductance14
- Ch 31: Alternating Current20
- Ch 33: The Nature and Propagation of Light17
- Ch 34: Geometric Optics29
- Ch 35: Interference13
- Ch 36: Diffraction19
- Ch 37: Special Relativity19
- Ch 38: Photons: Light Waves Behaving as Particles12
- Ch 39: Particles Behaving as Waves25
- Ch 40: Quantum Mechanics I: Wave Functions20
- Ch 41: Quantum Mechanics II: Atomic Structure21
- Ch 42: Molecules and Condensed Matter17
- Ch 43: Nuclear Physics13
- Ch 44: Particle Physics and Cosmology17
Young & Freedman Calc15th EditionUniversity PhysicsISBN: 9780135159552Non è quello che usi tu?Cambia libro di testo
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Young & Freedman Calc 15th EditionCh 25: Current, Resistance, and EMFProblema 34a
Young & Freedman Calc 15th EditionCh 25: Current, Resistance, and EMFProblema 34aCapitolo 25, Problema 34a
When a resistor with resistance is connected to a -V flashlight battery, the resistor consumes W of electrical power. (Throughout, assume that each battery has negligible internal resistance.) What power does the resistor consume if it is connected to a -V car battery? Assume that remains constant when the power consumption changes.
Guida verificata passo dopo passo1
Start by recalling the formula for electrical power consumed by a resistor: P = V^2 / R, where P is the power, V is the voltage, and R is the resistance.
Given the initial conditions with the flashlight battery: P = 0.0625 W and V = 1.50 V, use the formula to solve for the resistance R. Rearrange the formula to R = V^2 / P.
Substitute the known values into the rearranged formula: R = (1.50^2) / 0.0625.
Now, use the resistance R calculated from the flashlight battery scenario to find the power consumed when connected to the car battery with a voltage of 12.6 V. Use the formula P = V^2 / R again.
Substitute the car battery voltage and the previously calculated resistance into the formula: P = (12.6^2) / R, where R is the resistance found in step 3.
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Concetti chiave
Ecco i concetti essenziali che devi comprendere per rispondere correttamente alla domanda.
Ohm's Law
Ohm's Law states that the current through a conductor between two points is directly proportional to the voltage across the two points, and inversely proportional to the resistance. It is expressed as V = IR, where V is voltage, I is current, and R is resistance. This law is fundamental in calculating the current and understanding how voltage and resistance affect power consumption.
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Percorso guidato
03:07
Resistance and Ohm's Law
Power in Electrical Circuits
Electrical power is the rate at which electrical energy is transferred by an electric circuit. The power consumed by a resistor can be calculated using the formula P = VI, where P is power, V is voltage, and I is current. Alternatively, it can be expressed as P = V^2/R when the resistance is constant, which is useful for determining power consumption with different voltage sources.
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Percorso guidato
06:18Power in Circuits
Voltage Source Impact
The voltage source impacts the power consumed by a resistor. When the voltage increases, assuming resistance remains constant, the power consumed by the resistor increases quadratically according to the formula P = V^2/R. Understanding how different voltage sources affect power consumption is crucial for predicting changes in electrical circuits.
Video consigliato:
Percorso guidato
04:01Combining Voltage Sources in Series
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